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700gram = 0.7 kilogram

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Q: How do you prepare 100 ml of 1 in 1000 KMnO4?
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How do you prepare 100ml of 100ppm sol from 1000ppm sol?

By N1 V1 = N2 N2 1000 V1 = 100 * 100 V1= 100 * 100 / 1000 V1= 10 ml taken 10 ml from 1000 ppm and completed in 200 ml.


How many ml of 6.00m hcl are needed to prepare 1000 ml of a 100m hcl?

100 M HCl don't exist.


How to prepare 100 ppm solution of KMnO4?

To prepare a 100 ppm (parts per million) solution of KMnO4, you would dissolve 0.1 grams of KMnO4 in 1 liter of water. This concentration means there are 100 milligrams of KMnO4 dissolved in 1 liter of solution.


You have .2 n kmno4 which you have to dilute it to 0.05n kmno4 how can you dilute that?

To dilute 0.2N KMnO4 to 0.05N KMnO4, you can add 4 times the volume of water to the original volume of KMnO4 solution. For example, if you have 100 mL of 0.2N KMnO4, you would add 400 mL of water to achieve a 0.05N KMnO4 solution. Mix thoroughly to ensure uniform dilution.


What is 100 milliliters in liters?

1 l = 1000 ml ⇒ 100 l = 100 x 1000 ml = 100000 ml


How do you prepare solution of 1ppm from 1000 ppm solution?

Make a 1 to 100 dilution of the original 1000 ppm solution. That is take 1 ml and dilute to 100 ml, or take 10 ml and dilute to 1000 ml. This will give you a 10 ppm solution.


How many ml are there in 100 l?

1 litre = 1000 millilitres so 100 litres = 100*1000 = 100000 ml. Simple!


How many distilled water will be added to prepare 1000 ml 95 percent ethanol from 1000 ml 99 percent ethanol?

To prepare 1000 ml of 95% ethanol from 1000 ml of 99% ethanol, you will need to add 25 ml of distilled water to the 99% ethanol. This will bring the final ethanol concentration to 95%.


How do you prepare standard 0.1 N 100 ml Na2CO3 solution?

To prepare a 0.1 N 100 ml Na2CO3 solution, dissolve 5.3 grams of Na2CO3 in water and dilute to 100 ml. This will give you a solution with a concentration of 0.1 normal (N) for the 100 ml volume.


How many milliliters is 100 cL.?

V = ( 100 cL ) ( 1 L/100 cL ) ( 1000 mL/L ) = 1000 mL = 1.00 L


How much 95 percent alcohol must be used to prepare 1000 ml of 70 percent alcohol?

To prepare 1000 ml of 70% alcohol solution, you would need to mix 700 ml of 95% alcohol with 300 ml of water. Starting with a base of 95% alcohol ensures that the final solution will be at least 70% alcohol.


What is 0.1 liters in milliliters?

0.1 liters is equal to 100 mL (1 liter = 1,000 mL).