By N1 V1 = N2 N2 1000 V1 = 100 * 100 V1= 100 * 100 / 1000 V1= 10 ml taken 10 ml from 1000 ppm and completed in 200 ml.
100 M HCl don't exist.
To prepare a 100 ppm (parts per million) solution of KMnO4, you would dissolve 0.1 grams of KMnO4 in 1 liter of water. This concentration means there are 100 milligrams of KMnO4 dissolved in 1 liter of solution.
To dilute 0.2N KMnO4 to 0.05N KMnO4, you can add 4 times the volume of water to the original volume of KMnO4 solution. For example, if you have 100 mL of 0.2N KMnO4, you would add 400 mL of water to achieve a 0.05N KMnO4 solution. Mix thoroughly to ensure uniform dilution.
1 l = 1000 ml ⇒ 100 l = 100 x 1000 ml = 100000 ml
Make a 1 to 100 dilution of the original 1000 ppm solution. That is take 1 ml and dilute to 100 ml, or take 10 ml and dilute to 1000 ml. This will give you a 10 ppm solution.
1 litre = 1000 millilitres so 100 litres = 100*1000 = 100000 ml. Simple!
To prepare 1000 ml of 95% ethanol from 1000 ml of 99% ethanol, you will need to add 25 ml of distilled water to the 99% ethanol. This will bring the final ethanol concentration to 95%.
To prepare a 0.1 N 100 ml Na2CO3 solution, dissolve 5.3 grams of Na2CO3 in water and dilute to 100 ml. This will give you a solution with a concentration of 0.1 normal (N) for the 100 ml volume.
V = ( 100 cL ) ( 1 L/100 cL ) ( 1000 mL/L ) = 1000 mL = 1.00 L
0.1 liters is equal to 100 mL (1 liter = 1,000 mL).
To prepare 1000 ml of 70% alcohol solution, you would need to mix 700 ml of 95% alcohol with 300 ml of water. Starting with a base of 95% alcohol ensures that the final solution will be at least 70% alcohol.