Assuming the question is asking about Sea Water, the Wikipedia entry on "seawater" says "Seawateris water from a sea or ocean. On average, seawater in the world's oceans has a salinity of about 3.5% (35 g/L, or 599 mM). This means that every kilogram (roughly one litre by volume) of seawater has approximately 35 grams (1.2 oz) of dissolved salts...". So, to convert this to pounds and gallons, there are 3.78 liters per gallon and 16 ounces per pound. If I did the arithmetic correctly, that would be 0.28 pounds (4.5 oz) per gallon.
About 8.53 pounds.
8.556 pounds
Salt water is at it's lowest freezing point at a 23.3% salt-to-water solution. This works out to 2.28 lbs. of salt per gallon of water. Source: http://www.varitech-industries.com/pdfs/Salt%20Brine%20Statistics%20and%20Rock%20Salt.pdf
Salt brine typically weighs around 10.2 pounds per gallon, which is slightly heavier than water due to the addition of salt.
About 2.2 pounds of salt in a cubic foot of sea water. There are about 7.48 gallons in a cubic foot and sea water weighs about 8.5 pounds per gallon (63.58 pounds). Sea water is about 3.5 % salt (usually reported as 35 ppt or parts per thousand). So 63.58 x .035 = 2.2 pounds of salt.
Approximately 7.231 pounds The bulk density of table salt is 1.154 g/cm3. (http://en.wikipedia.org/wiki/Salt) One gallon is approximately 3785 cubic centimeters. Weight = Volume/Density=3785/1.154=3280. g [to four significant figures] There 453.6g per pound. So 3280.g=3280/453.6=7.231 pounds
3.5% (Atlantic Ocean) One gallon is about 8 pounds or 17.6 kg so there is about 600 grams (almost 22 oz.) of salt in the gallon.
The amount of salt in a barrel can vary depending on the size of the barrel and the type of salt. On average, a standard 55-gallon barrel could hold between 300-400 pounds of salt.
salt water has more mass because of the added salt so salt is heavier :)
Density = 8.345 lb/gallon (this is an odd density, because density changes depending on temperature, and this number is actually for 40°F water, but that's not relevant to this question)Density (d) = Mass (m) / Volume (V)d = m/Vm = Vdm = (1 gallon ) ( 8.345 lbs / gallon ) = 8.345 lbsThe water (without the salt) weighs 8.345 lbsIf you add 3 lbs of salt, you are just adding 3 lbs of salt. Just add 3 to the weight. This part is just to trip you up.8.345 + 3 = 11.345 lbsThe water with the salt weighs 11.345 lbs.
To determine how many pounds of candy will fit into a gallon jar, we first need to know the density of the candy in pounds per gallon. Then, we can divide the total weight capacity of the jar by the density of the candy to find the maximum amount of candy that can fit. Keep in mind that the actual amount may vary depending on the size and shape of the candy.
To determine the amount of salt needed for a 11,000-gallon pool, you typically aim for a salinity level of about 3,000 to 3,500 parts per million (ppm). This translates to approximately 30 to 35 pounds of salt for every 1,000 gallons of water. Therefore, for an 11,000-gallon pool, you would need about 330 to 385 pounds of salt. Always consult the manufacturer's guidelines for your specific saltwater system for precise measurements.