The answer is 118
The number of ways to choose 2 pens from 4 pens can be calculated using the combination formula ( \binom{n}{r} ), where ( n ) is the total number of items and ( r ) is the number of items to choose. Here, ( n = 4 ) and ( r = 2 ). Thus, the calculation is ( \binom{4}{2} = \frac{4!}{2!(4-2)!} = \frac{4 \times 3}{2 \times 1} = 6 ). Therefore, there are 6 ways to choose 2 pens from 4.
About $4 a pen and about $70 for a set.
a package of pens can range from $1 to $4, depending on quantity, brand, quality, and material.
one out of three
I HAVE THAT SAME PROBLEM! Let me guess, Keeping Skills Sharp. Wait, Where do you go to school?
29.5 x 2 = 59 14.75 x 4 = 59
1/4 of 64
The number is 59. Note that the LCM of 2, 3, 4, 5, and 6 is 60 60 = 2*2*3*5 so 59 = 60-1 should leave the given remainders: 59 = 2*29 + 1 (remainder=1) 59 = 3*19 + 2 (remainder=2) 59 = 4*14 + 3 (etc) 59 = 5*11 + 4 59 = 6*9 + 5
It is:(42*3)+1 = 59
The smallest number is LCM(2, 3, 4, 5, 6) + 1 = 61
60 pens. 60 2 = 30 60 3 = 20 60 4 = 15 60 5 = 12 60 6 = 10 - Chow
The factors of 236 are 1, 2, 4, 59, 118, and 236.The factor pairs of 236 are 1 x 236, 2 x 118, and 4 x 59.The proper factors of 236 are 1, 2, 4, 59, and 118 or,if the definition you are using excludes 1, they are 2, 4, 59, and 118.The prime factors of 236 are 2, 2, and 59. Note: There is repetition of these factors, so if the prime factors are being listed instead of the prime factorization, usually only the distinct prime factors are listed.The distinct prime factors of 236 are 2 and 59.The prime factorization of 236 is 2 x 2 x 59 or, in exponential form, 22 x 59.