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  1. Put an amount of water in a container of known cross-sectional area (eg a rectangular tank or a cylindrical tank) that is deeper than the object to measure.
  2. Mark where the water comes to.
  3. Put in the object of unknown volume so that it is completely submerged in the water.
  4. Measure the rise in water.
  5. Multiply the rise by the cross-sectional water to get the object's volume.

Alternatively:

  1. Fill a container to the brim with water
  2. Completely submerge the object in the water and collect all the displaced water in a measuring device.
  3. Read the volume of water spilled (displaced) out of the container which is the same as the volume of the object.
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Wiki User

11y ago

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More answers

The simplest method, for objects that are insoluble in water and denser than water, is the displacement method. It may be possible to get around the problem of solubility or density by using a different fluid.

Otherwise, you will need to decompose the object into smaller units whose volume is regular, calculate the volume of each unit and add them together.

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Wiki User

13y ago
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Yes--as long as they are homogeneous, too.

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Wiki User

15y ago
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  1. Fill a container with water
  2. Submerge object in water
  3. Measure change in water level

or in short we use WATER DISPLACEMENT METHOD

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Wiki User

13y ago
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Q: Is a method used to measure the volume of irregularly shaped objects?
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