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The math works like this Lets call the original two digit number x, then adding a "3" to the right of x would translate into x*10+3 hence we have x = (10x +3) -372 x + 372 = 10x+3 372= 10x+3-x 372-3=10x-x 396 = 9x 396/9=x x=41 and if we test it, 41 with the added 3 would be 413 and 413 - 372 = 41 is true The original two digit number was 41

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Q: The digit 3 is written to the right of a certain two-digit number thus forming a three-digit number the new number is 372 more than the original two-digit number What was the original two-digit num?
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