Put water in it then pour the water into a measuring beaker.
Additional answer
Assuming that by 'round' you mean it's a spherical, then use the formula 2/3rds x pi x r2.
The easy way: Pour the water into a graduated container, like a graduated cylinder, and read the volume directly. The hard way: Calculate the volume of a regularly shaped container (cylindrical or rectangular). Pour the water into the container. Measure the height of the water in the container. Calculate the volume of the unfilled portion of the container. Subtract this volume from the total volume of the container.
The volume is 4.19 cm3
When water is poured into a container, it occupies space within the container, causing the air volume to decrease. The air that was previously in the container is displaced by the water. If the container is sealed, the total volume remains constant, but the volume of air decreases as water fills the space. If the container is open, the air can escape, and the air volume may not change significantly.
I think it is the volume displacement. When you put an object into a container with a known volume of water, the water will rise, and that change of volume is the volume of the object you introduced into the container.
The shape and volume of water are determined by the container it is in. Water takes the shape of its container due to its ability to adapt to its surroundings and fill the space available. Its volume is determined by the amount of water molecules present within the container.
The container with the largest volume holds the most water.
volume of a rectangle container is 2520 cubic centimetres volume of water in millilitres is 2520000
The correlation between the volume of water poured into a container and the amount of empty space left in the container is inversely proportional. As the volume of water increases, the empty space decreases, assuming the container is filled to its capacity. When the container is full, there is no empty space left. This relationship illustrates the principle of volume conservation within a defined space.
Put solid in a container ; fill container with water to a known container volume; take object out of container and read the remaining volume. subtract this remaining volumefrom the known volume. This result is the volume of the regular or irregular shaped solid.
Put the object in a measuring container; pour in water to cover the object and measure the volume in the container; take the object out of container and measure the volume remaining. The difference is the volume of the object. If the object floats push it down until covered with water.
The volume of water will still be 250 mL once the ice melts. The ice will melt into water, but the total volume of the container will remain the same.
Strictly speaking, the volume of water will increase. For example, if you have a 200 gram chunk of ice floating in 1000 ml of water, the volume of the water itself is 1000 ml. When the ice melts, the volume of water will be 1200 ml. However, if you're asking whether the water level in the container will go up or down, the answer is "neither." The ice displaces an amount of water equal to the mass of the ice. When the ice melts, the mass does not chance, so the amount of the original water displaced by the melted ice does not change. Hence, the water level will remain the same.