Wiki User
∙ 11y agoIf it happens to be a hollow rectangular container with those dimensions, then
it can accommodate 11,880 cubic feet, or 440 cubic yards, or 8,845.7 gallons
of cargo inside.
Wiki User
∙ 11y agoIt is: 55*12*18 = 11,880 cubic feet
If you fill it to the brim, it would be 55 x 12 x 18 = 11880 cubic feet
12 swg current carrying capacity
The volume is 55*12*18 cubic feet = 11880 cu ft.
55' x 12' x 18' = 11,880 cubic feet = 440 cubic yards
Around 12-13 cubic feet
This question cannot be answered because there are no units for the measurements. It should be obvious to anybody that a capacity of a container which is 12 inches by 12 inches by 31 inches will be very different from that for one which is 12 feet by 12 feet by 31 feet, for example.
The carrying capacity of a box car that is 55 feet by 18 feet can be calculated by multiplying the length, width, and height. If the height of the box car is 9 feet, then the carrying capacity would be 8,910 cubic feet. Converting this to cubic yards by dividing by 27, the carrying capacity would be approximately 330 cubic yards.
Capacity = 55 ft * 12 ft * 18 ft = 55/3 * 12/3 * 18/3 cubic yards = 55*4*2 = 440 cubic yards.
You calculate square feet by muliplying the length of something by its width. for example a room 12 feet long by 9 feet wide would have an area of 12 x 9 square feet, which is 108 square feet.
80 x 80 x 12
The cubic capacity of a cylinder with inside dimensions of 8 ft diameter and 12 ft height is: Pi/4 x D2 x H = 0.785398*8*8*12 = 603.186 cubic feet (to nearest thousandth). or 192*Pi