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Using Ideal Gas Law: PV=mRT where P is pressure kPa, V is volume in m3, R is air gas constant in KJ/(kg*K), T is temperature in Kelvin. For 20 deg Celsius (= 293K) m=(PV)/(RT)=(101.325[kPa]*1[m3])/(0.287[kPa*m3/kg*K]*293[K]) m=1.205kg For 20 deg Fahrenheit (= 266.33K) m=(PV)/(RT)=(101.325[kPa]*1[m3])/(0.287[kPa*m3/kg*K]*266.33[K]) m=1.326kg

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Q: What is the mass of a cubic meter of air at 20 degrees?
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