Wiki User
∙ 9y agoIt is: 4/3*pi*3 cubed = 36*pi cubic units
Wiki User
∙ 9y agoVolume of the sphere: 4/3*pi*4 cubed = 268.083 cubic units rounded to 3 decimal place
radius is a scalar quantity, it can not have a negative value.
Surface area of the sphere: 4*pi*52 = 100*pi square units
It is 314.159 or 100*pi square units.
The volume is proportiuo9nal to the cube of the radius, so doubling the radiuscauses the volume to increase to (2)3= 8 times its original value.
To find the diameter of the sphere, you must calculate the cube root of the volume. The cube root of 20 is approximately 2.71. Therefore, the diameter of the sphere is twice this value, which is approximately 5.42 units.
Assuming a tin (Sn) atom is a sphere, its volume can be calculated using the formula for the volume of a sphere: V = 4/3 * π * r^3, where r is the radius of the sphere (which would be the known atomic radius of tin). Given a typical atomic radius for tin, you can plug this value into the formula to calculate the volume of a single tin atom.
No one because the volume of a sphere is 4/3*pi*radius cubed but it is only an estimation because the exact value of pi has never been found.
4/3*pi*radius3 = 523.6 Making the radius the subject of the above gives it a value of 5.000003897 or about 5 cm
To find the volume we must first work out what the radius is: 2*pi*radius = 929 Divide both sides by 2*pi to find the value of the radius: radius = 147.8549421 volume = pi*147.85494212*6 volume = 412071.7235 cubic units
Volume of a sphere equals 4 thirds times pi times the radius cubed. The radius here is 2 meters because the radius is one half the diameter. So plugging in the radius yields an exact result of 32pi ----- cubic meters 3 Or an equally correct but less precise value of 33.5103 cubic meters.
For the question to have any meaning, the volume should be in cubic metres, not metres. The surface area of a sphere of radius r is 4*pi*r*r and its volume is 4/3*pi*r*r*r. Use the second equation to find the value of the radius, r and then use that value in the first equation to calculate the surface area.