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When the image distance is negative, it indicates that the image is formed on the same side of the lens or mirror as the object, which typically means that the image is virtual. Virtual images cannot be projected onto a screen and are often upright and magnified. This situation commonly occurs with concave mirrors or converging lenses when the object is placed within the focal length.
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When is image distance negative in spherical mirrors?
In spherical mirrors, the image distance is negative when the image is formed on the same side as the object. This occurs in concave mirrors when the object is located between the focal point and the mirror, resulting in a virtual and upright image with a negative image distance.
How does the image distance compare to the object distance?
The image distance is the distance from the lens to where the image is formed, while the object distance is the distance from the lens to the object. In general, for real images, the image distance is different from the object distance. For virtual images, the image distance is negative and the object distance is positive.
Is image distance always taken as negative for concave mirror or lens?
In the case of concave mirrors, the image distance is typically taken as negative when the image is formed on the same side as the object (real image). However, for virtual images formed by concave mirrors, the image distance is considered positive. For concave lenses, the image distance is always taken as negative because they always produce virtual images on the same side as the object. Therefore, while there are specific conventions, the sign of the image distance depends on the type of image and optical device being used.
What is the Magnification equation for concave mirror?
The magnification equation for a concave mirror is given by the formula: M = - (image distance) / (object distance), where M is the magnification, image distance is the distance from the mirror to the image, and object distance is the distance from the mirror to the object. Negative magnification indicates an inverted image.
What is a negative lens is the same as?
If the lens equation yields a negative image distance, then the image is a virtual image on the same side of the lens as the object. If it yields a negative focal length, then the lens is a diverging lens rather than the converging lens in the illustration.
Why is negative sign associated with virtual image?
A negative sign is associated with a virtual image because the light rays do not actually converge at the location of the virtual image. Instead, they appear to diverge from a point behind the mirror or lens, creating the virtual image. Mathematically, this distance is represented as negative to indicate the direction of the virtual image.
Does the image size increase as the image distance increases?
No, the size of the image does not increase as the image distance increases. The size of the image is determined by the object distance, focal length of the lens, and the distance between the lens and the image plane.
What is an image negative?
A piece of photographic film having the negative (opposite) image of your positive print or image.
What is the difference between object distance and image distance?
image distance is the distance from the point of incidence on the mirror, the where the image is reflected to.object distance is the distance from the actual object being reflected to the point of incidence on the mirror where it's reflected as an image.
How do you calculate the manificiation?
Magnification is calculated using the formula: Magnification (M) = Image size (I) / Object size (O). It can also be expressed in terms of the focal lengths of the lens or mirror used, as M = - (Image distance (v) / Object distance (u)). A positive value indicates an upright image, while a negative value indicates an inverted image.
What is the sign for object and image distances that are measured on the front side of a mirror?
Regardless of which side of the mirror you designate as the positive side, one of them is positive and the other one is negative, since the object and image are always on opposite sides of the mirror. BTW ... If the mirror is flat, then their absolute values are equal.
What will happen to pinhole camera if the object distance is equal to image distance?
the image distance will appear the same
