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How do you calculate the number of grams of Al in 286 g of Al2O3 .?
To find the number of grams of Al, first calculate the molar mass of Al2O3 (2Al + 3O). Then, find the molar mass of Al. Divide the molar mass of Al by the molar mass of Al2O3 and multiply by 286 g to get the grams of Al in 286 g of Al2O3.
What is the mass in grams of 2.38 moles of Al2O3?
The answer is 242,6648 g.
What is the molarity of a solution in which 51 grams of aluminum oxide Al2O3 is dissolved in 500 mL of solution?
To find the molarity, you first need to calculate the number of moles of Al2O3. The molar mass of Al2O3 is 101.96 g/mol. Since you have 51 grams, that would be 0.5 moles. Next, convert the volume from mL to liters (500 mL = 0.5 L) and then divide the moles by the volume to get the molarity, which is 1.0 M.
What weight of aluminum may be obatained from 1kg of aluminum oxide?
The molar mass of Al2O3 is 101.96 g/mol. This means that 1kg of Al2O3 would contain approximately 9800 grams of Al2O3. From this amount, you can obtain 5400 grams (5.4 kg) of aluminum.
What does al2o3 stand for?
Aluminum oxide has the molecular formula of Al2O3. It is composed of aluminum (Al) and oxygen (O) and is 102.0 grams per mole.
Calculate the number of grams of Al in 371 g of Al2O3?
To calculate the number of grams of Al in 371 g of Al2O3, you first need to determine the molar mass of Al2O3 (102 g/mol). Then, calculate the molar mass of Al (27 g/mol). From the chemical formula Al2O3, you can see that there are 2 moles of Al for every 1 mole of Al2O3. Therefore, by using these ratios, you can determine that there are 162 g of Al in 371 g of Al2O3.
What is the mass in grams of 9.27 moles of Al2O3?
The molar mass of Al2O3 is 101.96 g/mol. To calculate the mass of 9.27 moles of Al2O3, you would multiply the moles by the molar mass: 9.27 mol x 101.96 g/mol = 945.442 g. So, the mass of 9.27 moles of Al2O3 is approximately 945.442 grams.
How many aluminum atoms are in 291.257 grams of Al2O3?
To calculate the number of aluminum atoms in 291.257 grams of Al2O3, first find the molar mass of Al2O3 (101.96 g/mol). Then, determine the number of moles of Al2O3 in 291.257 grams using the formula moles = grams/molar mass. Next, use the mole ratio from the formula Al2O3:Al (1:2) to find the number of moles of aluminum. Finally, multiply the number of moles of aluminum by Avogadro's number (6.022 x 10^23) to find the number of aluminum atoms.
How many grams of Al2O3 are formed from 3 moles of O2?
If the reaction is just between O2 and Al, the balanced equation would be:3O2 + 4Al -> 2Al2O3By using the coefficients of the equation, we see that from 3 moles of O2 we get 2 moles of Al2O3. To find out how much this is in grams, we need to find the molar mass of Al2O3 . This is just the sum of the atomic masses of each atom that makes it up. (Use a periodic table to find atomic masses) So we get:26.98*2+16*3= 102.0One mole equals 102g, so the 2 moles produced by the reaction would amount to 204g.
How many grams of oxygen are needed to produce 95.6 g of aluminum oxide?
To find the amount of oxygen needed to produce 95.6 g of aluminum oxide (Al2O3), first calculate the molar mass of Al2O3 (101.96 g/mol). Then, set up a ratio using the molar mass ratio of oxygen to Al2O3 (3:2). Calculate the amount of oxygen needed using the given mass of Al2O3 and the molar ratio.
How many grams of aluminum are in 25.0g of aluminum oxide?
To find how many grams of aluminum are in 25.0g of aluminum oxide, first, determine the molar mass of aluminum oxide (Al2O3), which is 101.96 g/mol. Next, calculate the molar mass of aluminum (Al), which is 26.98 g/mol. Then, set up a ratio using the molar masses to find the amount of aluminum in 25.0g of aluminum oxide: (2 mol Al / 1 mol Al2O3) x (26.98 g Al / 101.96 g Al2O3) x 25.0g Al2O3 = 6.63g of aluminum.
What is the mass of AlCl3 that is produced when 25.0 grams of Al2O3 reacts with HCl according Al2O3 6HCl to 2ALCl3 3H2O?
To find the mass of AlCl3 produced, first calculate the molar mass of Al2O3 and AlCl3. Then, use stoichiometry to determine the moles of AlCl3 produced. Finally, convert moles of AlCl3 to grams using its molar mass. The mass of AlCl3 produced will be 12.25 grams.
