94.99% of an 8oz. cup
The mean and standard deviation. If the data really are normally distributed, all other statistics are redundant.
BMI varies from person to person and one measure of this variability is the standard deviation. Assuming the BMI is approximately normally distributed, only around 0.135% of the people will have results that are -3 sd or lower.
Yes, to approximately standard normal.If the random variable X is approximately normal with mean m and standard deviation s, then(X - m)/sis approximately standard normal.
A food processor packages orange juice in small jars. The weights of the filled jars are approximately normally distributed with a mean of 10.5 ounces and a standard deviation of 0.3 ounce. Find the proportion of all jars packaged by this process that have weights that fall below 10.875 ounces.
The Miller Analogies Test scores have a mean of 400 and a standard deviation of 25, and are approximately normally distributed.z = ( 351.5 - 400 ) / 25 = -1.94That's about the 2.6 percentile.(Used wolframalpha.com with input Pr [x < -1.94] with x normally distributed with mean 0 and standard deviation 1.)
68.2%
A particular fruit's weights are normally distributed, with a mean of 760 grams and a standard deviation of 15 grams. If you pick one fruit at random, what is the probability that it will weigh between 722 grams and 746 grams-----A particular fruit's weights are normally distributed, with a mean of 567 grams and a standard deviation of 25 grams.
There are approximately 16.4% of students who score below 66 on the exam.
(X-61)/10.2=.878 X = 69.95 approximately 70
d. All the above.
It is not! It is very approximately so and the key word there is approximately.
In a normal distribution, approximately 68% of the data falls within one standard deviation of the mean. Given a mean height of 65 inches and a standard deviation of 2.5 inches, this means that approximately 68% of women will have heights between 62.5 inches (65 - 2.5) and 67.5 inches (65 + 2.5).