probably a supersaturated solution if you heat it to dissolve all of the salt
You have said yourself that is about 200 grams.
The more concentrated solution is the one containing 18 grams of salt and 90 grams of water. This is because the concentration of the solute (salt) is higher in this solution compared to the solution containing 5 grams of salt and 10 grams of water.
200 grams X 0.10 = 20 grams
The solubility of NH4Cl in water at 50°C is approximately 74 grams per 100 grams of water. To make a saturated solution, you would need to dissolve 148 grams of NH4Cl in 200 grams of water.
Only if you have pure water in mind: 200 cc = 200 milliliters of pure water weigh 200 grams.
200 grams of water is approximately equals to 219 mili litre.
At 60 degrees Celsius, the solubility of potassium chlorate (KClO₃) in water is approximately 7.2 grams per 100 grams of water. To create a saturated solution in 200 grams of water, you would need about 14.4 grams of potassium chlorate (7.2 g/100 g water x 200 g water = 14.4 g KClO₃). Thus, 14.4 grams of potassium chlorate would be required for saturation at this temperature.
There are 200 grams in 200 grams.
That is 40 teaspoons.
The conversion of grams to milliliters depends on the density of the substance. If you're dealing with water, which has a density of 1 g/mL, then 200 grams would be equal to 200 milliliters. However, for other substances, you need to know the density to make the conversion.
Add 200 grams of the salt to 800 g of water, mix and dissolve, and you've got your desired 20% solution.
That is approximately 2/5 of a pint