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I will use this formula. Some conversion will be required. ( I only know specific heat iron in J/gC )

q(Joules) = mass * specific heat * change in temperature Celsius

3 kilograms cast iron = 3000 grams

q = (3000 g)(0.46 J/gC)(120 C - 30 C)

= 124200 Joules (1 kilojoule/1000 joules)

= 124.2 kilojoules of energy needed

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