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How many kilojoules of energy are necessary to raise the temperature of 3 kilograms of cast iron from 30 degrees celsius to 120 degrees celsius?
Chulena40
I will use this formula. Some conversion will be required. ( I only know specific heat iron in J/gC )
q(Joules) = mass * specific heat * change in temperature Celsius
3 kilograms cast iron = 3000 grams
q = (3000 g)(0.46 J/gC)(120 C - 30 C)
= 124200 Joules (1 kilojoule/1000 joules)
= 124.2 kilojoules of energy needed
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∙ 12y ago
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