V=1/3(l+wl) v=1/3l(1+w) 3v=l(1+w) 3v/(1+w)=l
6 plus w
6 + w - 2w - 11 + 6w = -5 + 5w
Well, darling, the quotient of 100 and the quantity 6 plus w is technically 100/(6+w). So, if you want to keep it mathematically sassy, there you have it. Just plug in your value for w and let the numbers do the talking.
100/6+ w
Ah, math time, my favorite! To reduce the fraction w^2 + 5w + 6 over w^2 - w - 12, first factor both the numerator and the denominator. The numerator factors into (w + 2)(w + 3), and the denominator factors into (w + 3)(w - 4). Cancel out the common factor of (w + 3) in both the numerator and the denominator, leaving you with (w + 2) over (w - 4). Voilà!
w+3=w+6 obviously doesn't equal itself... subtract w from both sides and you are left with 3=6 So the answer is NO SOLUTION, or as a set, it is the empty or null set.
One answer is : 6x+6y + wx+wy = (6+w)x + (6+w)y.
100/(6+w)
w + 3 = 4w - 6 9 = 3w w = 3
It is (6 + w) - 14
-3