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Should be 1/16 of it's volume. Using similar triangles, you can find that the radius for water is .75 inches. Then, using V=(1/3)*pi*h*r^3 for the volume of the cone and dividing the volume of water by the total volume of the cone, you should get:

Vw/Vt = (hw*rw^3)/(ht*rt^3)

where all the values with w are the water ones and all the variables with t are for the whole cone.

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15y ago

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