The associative law of addition refers to the fact that numbers can be grouped in different combinations and the answer will still be the same.
Commutative Law: a + b = b + a Associative Law: (a + b) + c = a + (b + c)
The associative law holds for all numbers. There are operations that it may not hold for, but that is an entirely different matter.
pata bahi yar
there are 3 laws of arithmetic. These are Associative law, Distributive Law and Cummutative law.
For any three numbers a, b, and c:a + b = b + a (commutative law)(a + b) + c = a + (b + c) (associative law)Both the commutative and associative laws are also valid for multiplication.a x (b + c) = (a x b) + (a x c) (distributive law)For any three numbers a, b, and c:a + b = b + a (commutative law)(a + b) + c = a + (b + c) (associative law)Both the commutative and associative laws are also valid for multiplication.a x (b + c) = (a x b) + (a x c) (distributive law)For any three numbers a, b, and c:a + b = b + a (commutative law)(a + b) + c = a + (b + c) (associative law)Both the commutative and associative laws are also valid for multiplication.a x (b + c) = (a x b) + (a x c) (distributive law)For any three numbers a, b, and c:a + b = b + a (commutative law)(a + b) + c = a + (b + c) (associative law)Both the commutative and associative laws are also valid for multiplication.a x (b + c) = (a x b) + (a x c) (distributive law)
The associative law states that the order in which elements are grouped does not affect the outcome of an operation. In mathematics, this law is commonly used in addition and multiplication. For example, (a + b) + c is equal to a + (b + c), and (a * b) * c is equal to a * (b * c).
Any pair can added first (Only applies for addition)
(1 + 2) + 3 = 1 + (2 + 3)
Both union and intersection are commutative, as well as associative.
Depends on what you find addicting, and how you classify addicting...
no the answer is no because you can fine a-b and b-a individually but in general they are not equal By Habib