Any number can be the next number since given any number whatsoever, it is possible to find a polynomial of order 5 that will fit the above sequence and the additional "next" number.
The simplest solution for the 5 numbers in the given sequence is that the sequence is generated by the rule:
Un = n3 + n2 + n for n = 1, 2, 3, ...
In that case the next number is 258.
But, for example, if I want the next number to be 2013 (the current year), all I need to do is to define the rule as:
Un = (117n5 - 1755n4 + 9953n3 - 26317n2 + 32066n - 14040)/8 for n = 1, 2, 3, ...
5, 6, 7, 8, 10, 11, 14, 15, 18, 19, 20, 21, 22, 23, 24, 26, 27, 28, 30, 31, 32, 33, 34, 35, 37, 38, 39, 41, 42, 43, 44, 45, 46, 47, 50, 51 OR 5, 6, 7, 8, 10, 11, 14, 15, 18, 20, 23, 26, 29, 32, 36, 39, 44, 47, 53, 57, 63, 68, 74, 80, 87, 93, 101, 107, 116, 123, 133, 141, 151, 160, 171, 181, 193, 203, 216, 227, 241, 253, 268, 281, 297, 311 or 5, 6, 7, 8, 10, 11, 14, 15, 18, 20, 25, 27, 33, 35, 43, 47, 56, 62, 71, 80, 92, 103, 118, 132, 149, 168, 190, 212, 240, 267, 300, 336, 375, 419, 468, 521, 580, 646, 717, 798, 885, 981, 1087, 1204, 1332, 1473, 1626, 1797, 1980, 2187, 2405 The last one is Expansion of Product_{ n >= 2, n not of the form 2^k-1 } (1+x^n). The second one is Expansion of 1/((1-x)(1-x^2)(1-x^5)(1-x^12)). And the first one is nonsquares mod 52. This is a great question for showing that a sequence is not unique. This is a sequence not a series since there is not indication we are adding any terms.
The next number in the series 10, -5, 25, -35, 85, -155 is:
Given any number it is easy to find a polynomial rule of order 5 such that the first five numbers are as listed in the question and the sixth is the given number. That is, I can find a rule so that any number can be the "next" in the sequence.The simplest solution, using a cubic equation isUn = n3 + n2 + n for n =1, 2, 3, ...Accordingly, the next term is 258.
how do I get the answer for this question? find the equivalent number on the 12 hour clock for 155
For any number n, the numbers fit the formula (n-1)3+(n-1)2+(n-1). Therefore, the seventh number in the series is equal to 63+62+6 = 216 + 36 + 6 = 258.
To find the number that, when multiplied by 3, equals 155, you would divide 155 by 3. So, 155 Γ· 3 = 51.6667. Therefore, the number that, when multiplied by 3, equals 155 is approximately 51.6667.
155 is a composite number. Its factors are 1, 5, 31, and 155.
155 is not a prime number, but a composite number, as it is divisible by 5 and 31.
18% of 155 = 18/100 * 155 = 27.9
It is already rounded to a whole number as 155
As 155 is ending with 5 then it can be divided by 5 thus it's not a prime number 155 = 5 x 31
It is: 5*31 = 155
5 is an odd number so therefore 155 is an odd number.