Well first of all, you should know that anything raised to the 0th power is 1. So the answer is 0: 7^0=1.
But if the answer's not so obvious, you should use logarithms. If 7^x=1, then the log (7) of x = 1. So you'd just find the inverse log (base 7) of 1.
Some calculators can do that, some can't. The ones that can't usually can only find the log of a number in base 10 or base e (which is ~2.7182818), so you'd have to do a logarithmic conversion.
To do a logarithmic conversion, you'd have to use the base conversion formula: log (base 7) of x = log (base 10) of x/log (base 10) of 7. Both sides of that equation equals 1 because of the information that you're giving me.
So...
log (base 10) of x/log (base 10) of 7 = 1.
Using algebra, we're going to try to get x by itself on one side of the equation. We'll start by getting rid of the denominator by multiplying both sides by log (base 10) 7. The result:
log (base 10) of x = 1
We'll isolate x from the logarithm by taking the inverse log of the left side. We'll take the inverse log of the right side to maintain the equality.
x = log inverse (base 10) of 1.
You can use a calculator for that. Well, you COULD, but you should have remembered that the log inverse of 1 with base ANYTHING is 0, right?
x = 0.
When you're trying to visualize what's going on, always remember that logarithms are exponents. If 10^2=100, then "2" in that previous equation is a logarithm; it's the base 10 logarithm of 100; log (base 10) of 100 = 2. It's basically a way of switching around the order that each number comes in. That may help you keep this new mathematical language in perspective.
To find the missing base of an exponent, you can use logarithms. If you have an equation in the form ( a^x = b ), where ( a ) is the base and ( b ) is the result, you can take the logarithm of both sides: ( x \log(a) = \log(b) ). Then, solve for the missing base ( a ) by rearranging the equation, which may involve exponentiation or using properties of logarithms. Alternatively, if you have a specific value for the exponent and result, you can also use trial and error or graphing methods to estimate the base.
When you write 53 , the whole thing is called a power. The 5 is the base, and the 3 is the exponent.
The exponent can only be found in the context of a base. But there is no base specified and so there can be no clear answer.On possible answer is that 262144 = 512^2 so, with the base 512, the exponent is 2.
It is: 73 = 343
If you are referring to the number 125 itself, then 125 is the base, and 1 is the exponent. This would be written as 1251. This number can also be written as 53, as 5 cubed also equals 125. In this case, 5 is the base, and 3 is the exponent. The main integer value is the base, the number to the upper right of it is the exponent. The exponent tells you how many times to multiply the base number by itself to find the answer.
That can't be answered. The volume of the base of what kind of base?
You can but it has no particular significance.
The main use for a logarithm is to find an exponent. If N = a^x Then if we are told to find that exponent of the base (b) that will equal that value of N then the notation is: log N ....b And the result is x = log N ..........b Such that b^x = N N is often just called the "Number", but it is the actuall value of the indicated power. b is the base (of the indicated power), and x is the exponent (of the indicated power). We see that the main use of a logarithm function is to find an exponent. The main use for the antilog function is to find the value of N given the base (b) and the exponent (x)
Depends on the exponent and the base. 23 = 2x2x2 = 8 0.52 = 0.5 x 0.5 = 0.25 Some will have decimals, some will not.
To find the exponent of a number, we typically look for its prime factorization. However, the term "exponent" can also refer to the exponent in the context of a specific base. If you want to know the exponent in the context of prime factorization, you would need to factor the number first. If you meant something else by "exponent," please provide more context for a precise answer.
To find the base number when the number is 729 and the exponent is 3, you need to calculate the cube root of 729. The cube root of 729 is 9, since (9^3 = 729). Therefore, the base number is 9.
In this context, the "E" in the equation y = 6E-0.5x + 0.0029 represents scientific notation. It is used to denote a number in the form of a * 10^b, where 'a' is the coefficient and 'b' is the exponent. Therefore, 6E-0.5 can be rewritten as 6 * 10^(-0.5). This indicates that the coefficient is 6 and the exponent is -0.5.