you can write it in the form
y=mx+b
where y and x are constants, m is slope, and b is the y-intercept
you can find the slope (m) by taking y1-y2/x2-x1 with any 2 points on the graph ( it doesn't matter which point comes first)
if you have a graph, to find b (y-int) locate the point where x equals zero, if there is none, than the y-int is zero
if you don't have a graph plug in m along with any point on the graph to find b
Graph both equations on the same graph. Where they intersect is the solution to the system of equations
You can use a graph to solve systems of equations by plotting the two equations to see where they intersect
You can.
One can solve equations of motion by graph by taking readings of the point of interception.
No, thank you.
Equations = the method
The statement - The graph of a system of equations with the same slope and the same y intercepts will have no solution is True
Press Y= to see the equations. Enter and equation in, using x as the variable. (Press X,T,θ,n for an x.) Enter an equation and press GRAPH to see it. (If you need to graph parametric, polar, or sequential equations, press MODE and select the graph type you need. Select FUNC for normal y= equations.)
You graph each of them separately, on the same coordinate plane.
The statement "A system of linear equations is a set of two or more equations with the same variables and the graph of each equation is a line" is true.
Yes.
Graph the equations and see where they meet. Substitute back into both equations