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This one's pretty easy if you have a picture of a pyramid. For your stereotypical rectangular pyramid: For vertices (corners) Tip=1 Base=4 Which makes 5 vertices (vertexes). For the faces Base = 1 Plus 4 sides Yields 5 faces. If I replace the 4 with a variable, "n", I get an algebraic rule describing the number of faces, or corners, for any pyramid with an n-gon base: sides/vertices = n+1 If I have a triangular pyramid (a 3-gon base), then the sides and vertices are 4 in number (this is my favorite kind: you can make a pyramid with 4 equiangular/equilateral triangles, it's called a regular tetrahedron!). For a pentagon (a 5-gon), we get 5 + 1 = 6; for a hexagon, it's 7; for a heptagon (n=7) we get 8; octagon, 9; nonagon (n=9), 10; decagon (n=10), 11; 11-gon gives 12; blah blah blah...

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15y ago
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14y ago

A square pyramid has 5 corners, and 5 faces.

A triangular pyramid has 4 corners, and 4 faces.

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13y ago

It has 5 faces 8 edges and 5 points

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Q: How many corners and faces does a pyramid have?
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