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The bowl is tipped by 35 deg so the diameter of the bowl makes a 35 deg angle with the horizontal. The surface of the water must be horizontal and so that makes an angle of 35 deg with the tipped diameter.

Therefore [in cross section] the water occupies a segment of a circle such that the angles between the water surface and the radii at both ends on the segment are 35 deg. Therefore the segment subtends an angle of 110 deg at the centre. Also, the radii are 20 cm.

In the triangle formed by the water surface and the sides of the segment, the distance from the centre of the bowl to the water surface is 20*sin(35) = 11.47 cm. Therefore, the depth of the water is 20 - 11.47 = 8.53 cm.

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