4+2+1 = 7
(-5)*(-4) / [(-7) + 2] = (-5)*(-4)/(-5) = (-4) or -4.
I am a 3 digit number divisible by 7 but not 2 the sum of my digits is 4 what number am I
1+2+4 = 7
It is: 2 to the power 4 times 7 to the power 2 = 784
3 + 4 = 7 7 x 2 = 14
Two integers that have a sum of -7 and a product of 12 are -3 and -4.
4 & 7
The sum of 5/7 and 2/4 is 1 3/14
4 and 3(4 + 3 = 7)or 1 and 6(1 + 6 = 7)or 5 and 2(5 + 2 = 7)
SUM means plus 4+7=11
To find 4 times the sum of y and 7, you first calculate the sum of y and 7, which is y + 7. Then, you multiply this sum by 4 to get the final result. Therefore, the expression for 4 times the sum of y and 7 is 4(y + 7), which simplifies to 4y + 28.