First find the number which is 1/3 of 51. This is 17. Thus any three numbers which average 17 will always add up to 51. For the numbers to be consecutive and have an average of 17, the middle number must be 17 and the two remaining numbers are 17-1 and 17+1 ie 16 and 18. So the three consecutive numbers are 16, 17 and 18.
16,17,18
The integers are 51, 53 and 55.
They are: -15-17-19 = -51
51 / 3 = 1716+17+18 = 51
The integers are 16, 17 and 18.
51
The only proper factor of 51 that is less than 1/3 of 51 is 3. Divide the sum of three consecutive odd integers by 3: 51/3 = 17. The smallest of these integers will be two less than 17 and the largest will be two more than 17, so the three consecutive odd integers having a sum of 51 are 15, 17, and 19.
50 + 51 + 52 = 153
Divide the sum of the three consecutive odd integers by 3: 51 / 3 = 17. The smallest of these integers will be two less than 17 and the largest will be two more than 17, so the three consecutive odd integers will be 15, 17, and 19.
The consecutive integers whose sum is 51 are 16, 17, and 18.
Divide the sum of the three consecutive odd integers by 3: -147 /3 = -49. The smallest of these integers will be two less than -49 and the largest will be two more than -49, so the three consecutive odd integers will be -47, -49, and -51.
X + (X + 1) + (X + 2) = 156 3X + 3 = 156 3X = 153 X = 51 51 + 52 + 53 = 156 156 = 156 51, 52, 53 ------------------are your three consecutive integers