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AREA = L * W
You know that "W" is the width. So all you need is the length. The parimeter of any rectangle is two widths (2W) plus two lengths (2L). So, in other words:
2W + 2L = 200.
But we only need one of each, so we divide the perimeter by "2" to determine what one width and one length would be:
L + W = 100.
Now that we know that, one length (the missing part of our equation) is:
L = 100 - W
Put it all together, and we get:
AREA = L * W
AREA = (100 - W) * W
What else can I help you with?
The perimeter of a rectangle is 200 inches the length exceeds the width by 96 inches?
Length + width = half perimeter = 100". Length is 98", width is 2"
What is the perimeter of 24cm by 100cm?
248cm. Why? Because it is a rectangle so the perimeter is length + length + width + width or just widthx2 + lengthx2. So, 24x2=48 and 100x2=200. 200+48=248cm.
If 2 rectangles have the same area must they have the same perimeter?
Not at all.Rectangle A:-- Length = 20-ft, Width = 10-ft.-- Area = 200 square ft-- Perimeter = 60-ftRectangle B:-- Length = 16-ft, Width = 12.5-ft-- Area = 200 square ft-- Perimeter = 57-ftRectangle C:-- Length = 40-ft, Width = 5-ft-- Area = 200 square ft-- Perimeter = 90-ftRectangle D:-- Length = 50-ft, Width = 4-ft-- Area = 200 square ft-- Perimeter = 108-ftRectangle E:-- Length = 100-ft, Width = 2-ft-- Area = 200 square ft-- Perimeter = 204-ftRectangle F:-- Length = 800-ft, Width = 3 inches-- Area = 200 square ft-- Perimeter = 1600-ft 6-in
What is 200 feet by 240 feet in area and perimeter?
A rectangle measuring (200-ft x 240-ft) has Area = 48,000 square ft Perimeter = 880 ft
The width of a rectangle is half as long as the length the rectangle has an area of 200 square feet what are the length and width of the rectangle?
Let the width be 2x and the length be x: width*length = area 2x*x = 200 sq ft 2x2 = 200 Divide both sides by 2 and then square root both sides: x = 10 Therefore: length = 10 ft and width = 20 ft
If you have a rectangle whose Perimeter equals 60 and the Area equals 200 what are the lengths of the four sides?
The rectangle must have sides with lengths of 20, 20, 10, and 10. 20+20+10+10 = 60 (perimeter) 20*10 = 200 (area)
What is the area of a rectangle measuring 25 feet long by 8 feet wide?
The area of rectangle is : 200.0
Can you calculate the area if you know the perimeter?
No, you can not calculate an area if you know just the perimeter. For example, rectangle with sides of 10 and 20 would have a perimeter of 60 and an area of 200, but a square of sides 15 would have a perimeter of 60 and an area of 225. You need to know more details about the shape than just the perimeter.
What are the dimensions of a rectangle with perimeter 200 feet and area less than 100 square feet?
To find the dimensions of a rectangle with a perimeter of 200 feet, we can use the formulas for perimeter (P = 2(l + w)) and area (A = l * w). Given that the perimeter is 200 feet, we have ( l + w = 100 ). However, for the area to be less than 100 square feet, the dimensions must be such that ( l * w < 100 ). Since the maximum area occurs when ( l ) and ( w ) are equal, the dimensions would need to be less than 10 feet each, which is not possible under these constraints. Therefore, no rectangle can satisfy both conditions.
The length of a rectangle is 100cm what is the width of the rectangle if the perimeter is 6 times the width?
P = 2(100 + W) and P = 6W so 200 + 2W = 6W making 4W = 200 so W = 50 cm.This suggests that in any rectangle with a length twice the width, the perimeter is 6 times the width. eg 56 x 28: 56 + 28 = 84 x 2 = 168 = 6 x 28.Simple proof: P = 2 (L + W) but L = 2W so P = 2 (2W + W) = 2 x 3W = 6W. QED
Jim has designed a rectangle with an area of 100 square feet and a perimeter of 401 feet is it possible that Jim's rectangle has whole number side lengths?
No it is not possible the dimensions are 200 by 1/2
What is the perimeter of an oblong buikding that is 45 m wide and 55m long?
To find the perimeter of an oblong building, you can use the formula for the perimeter of a rectangle, which is P = 2(length + width). For a building that is 45 m wide and 55 m long, the perimeter would be P = 2(55 m + 45 m) = 2(100 m) = 200 m. Therefore, the perimeter of the building is 200 meters.
