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The three bisectors meet at a point which is the centre of the circle.

is you draw the circle that has that point as centre and 1 of the corners as a point on the circle, all corners will be on the circle

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14y ago

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The intersection of the angle bisectors of a triangle?

The intersection of the angle bisectors of a triangle is called the incenter. It is equidistant from the sides of the triangle and can be constructed by drawing the angle bisectors of the triangle's angles. The incenter is the center of the incircle, which is the circle inscribed within the triangle.


The orthocenter is the point shared by the angle bisector of a triangle?

Actually, the orthocenter of a triangle is the point where the three altitudes of the triangle intersect. The altitudes are perpendicular lines drawn from each vertex to the opposite side. The angle bisectors of a triangle intersect at the incenter, not the orthocenter.


The point of concurrency for perpendicular bisectors of any triangle is the center of a circumscribed circle?

Yes, that's correct. The point of concurrency for the perpendicular bisectors of a triangle is called the circumcenter, and it is the center of the circumscribed circle of the triangle.


Circles circumscribed about a given triangle will all have centers equal to the incenter but can have different radii?

Yes, that is correct. Circles circumscribed about a given triangle will have centers that are equal to the incenter, which is the point where the angle bisectors of the triangle intersect. However, the radii of these circles can vary depending on the triangle's size and shape.


The lines containing the altitudes of a triangle are concurrent at this point?

The point where the altitudes of a triangle intersect is called the orthocenter. This point is concurrent, meaning the three altitudes intersect at this single point inside or outside the triangle. The orthocenter is different from the centroid, circumcenter, and incenter of a triangle.