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How does ic 7405 work with pin configuration?
The 7405 is a hex inverter with open collector-outputs, the I/O's is as follow:Input Inverted outputPin1=A1 Pin2=Y1Pin3=A2 Pin4=Y2Pin5=A3 Pin6=Y3Pin9=A4 Pin8=Y4Pin11=A5 Pin10=Y5Pin13=A6 Pin12=Y6Power pinsPin14=Vcc +Pin 7=GND
How many half adder to make full adder?
binary addition of two bits is called a half adder ,and of three bits is called a full adder to be more lucid in my explanation a half adder doesnot consider a carry generated from the previous added pair of binary numbers consider an example :- A=a1a2a3a4 + B=b1b2b3b4 = sum=s1s2s3s4 the actual addition procedure is a4 and b4 are added first then the sum is stored in s4 and the generated carry is added with a3 and b3 and the process continues so addition of a4 and b4 where there is no input carry is carried out by half adder and the addition of c1+a3+b3 is carried out by full adder. but practiclly the first situation a4+b4 can be considered as a4+b4+0 so all the addition can be performed by full adder it self truth table for both half adder A B s c 0 0 0 0 0 1 1 0 1 0 1 0 1 1 0 1 for full adder c1 A B s c 0 0 0 0 0 0 0 1 1 0 0 1 0 1 0 0 1 1 0 1 1 0 0 1 0 1 0 1 0 1 1 1 0 0 1 1 1 1 1 1 where s and c can be viewed as the sum and carry on solving the k-map for full adder and half adder we can obtain the fuctions of sum and carry
