If you are referring to the removal of lamps from the lamp-holder then yes a very light coating of a high temperature grease will help. This problem arose when the lamps came with aluminum screw bases and the lamp-holder manufactures decided to use aluminum on their screw shells instead of the old brass ones. Aluminium screwing into aluminum creates a condition called spalling and the two surfaces tend to weld together. By applying a very light coating of lithium grease to the lamp when installing the bulb will help when removing the bulb when its life is finished.
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It has components that are arranged end to end in order to produce light.
Take two pieces of wire, one battery and one light bulb. Battery and light bulb should be the same voltage. Attach one end of one piece of wire to one pole of the battery (Soldering it would be best). Attach one end of the other piece of wire to the other pole of the battery and the other end of the wire to side conductor of the light bulb. You are done. To test the conductivity of something you simply touch the center conductor of the light bulb to one end of what you're testing and the other end of the first piece of wire to the other end of what you're testing. If what you're testing conducts electricity the current will run from the battery through what you're testing into the light bulb, out the other side of the light bulb and back to the battery and the light bulb will light up. If what you're testing doesn't conduct electricity, the electricity from the battery will not be able to pass through it to the light bulb and it won't light up. Good luck!
A flashlight is a series circuit. The batteries positive end connects to the flashlights switch. The switch connects to the center pin of the light bulb. The bulb filament is connected to the center pin of the bulb and the outer metal shell of the bulb socket. The shell of the bulb socket is connected to the metal flashlight's body which returns to the negative end of the battery. Turn on the switch and you have light.
Diagrams are not supported with WikiAnswers, sorry, so you will have to use your imagination...A simple series circuit can be built with a battery, a switch, and a light bulb. One end of the battery is connected to one end of the switch. The other end of the switch is connected to one end of the bulb. The other end of the bulb is connected to the other end of the battery.If the switch is open, no current flows, and the bulb does not illuminate. If the switch is closed, current flows, and the bulb illuminates. By Ohm's law, the current through the bulb is proportional to the battery voltage and inversely proportional to the resistance of the bulb. Note, of course, that we are talking about hot resistance of the bulb, because cold resistance is an entirely different thing, due to the temperature coefficient of the bulb. Also, by Kirchoff's current law, the current at every point in this simple series circuit is the same and, by Kirchoff's voltage law, the voltage across the battery is the same as the voltage across the bulb.
In order to know why fluorescent bulbs turn black at the end, you need to understand how they work. Basically, when you turn on the lighht switch, the ballast sends a spark through the mercury-vapor-filled tube or bulb, depending on design. When it does this, it creates light by activating phosphors that coat the inside of the tube. Well each time the ballast fires, it creates emissions. These emissins materials then settle on the surface inside the glass. After awhile this material piles up. When it does this, the tube end turns completely black. Not only does the tube end turn black, but the accumulated materials pile up so high that it blocks the electrons that flow into the mercury. When this happens, you will notice the bulb or tube flicker heavily and then burn out.