Sure. In a two-wire circuit, both wires carry equal currents.
Plastic wrapped around the wire is insulator. Not a conductor. That is why it is wrapped around the conductor wire.
Capacitance exists between any two conductors, current carrying or not.
Capacitance is an ability to store an electric charge. "If we consider two same conductors as capacitor,the capacitance will be small even the conductors are close together for long time." this effect is called Stray Capacitance.
1. phase identification test. 2. Insulation Resistance Test. 3. Conductor capacitance. 4.Conductor Resistance. 4. Outer Sheath Test.
capacitance will tend to zero
Of the three choices, capacitance does not limit current flow in an AC circuit.
The radius in the eqn. of capacitance is actual outside radius of the conductor whereas for inductance eqn. The radius is the self GMD of the conductor.
capacitance also increase
Sure. In a two-wire circuit, both wires carry equal currents.
The capacitance of a wire is directly related to its ability to store electrical charge. A wire with higher capacitance can store more charge, while a wire with lower capacitance can store less charge. This relationship is important in understanding how electrical systems work and how they can be optimized for different applications.
Yes, wire is a conductor of electricity.
Yes, a wire is a conductor because it allows electricity to flow through it.
Wire can be either an insulator or a conductor, depending on its material and properties. Copper wire, for example, is a good conductor of electricity, while rubber-coated wire is used as an insulator to protect against electric shocks.
It matters what kind of wire like a cell phone charger would not be a conductor but a wire made for braces would be a big conductor. Also anything metal is a positive conductor of electricity. :)
A wire is typically a conductor, meaning it allows electricity to flow through it.
The capacitance of a twin copper wire would depend on various factors such as the distance between the wires, the diameter of the wires, and the dielectric material between them. It can be calculated using the formula C = (ε0 * εr * A) / d, where C is the capacitance, ε0 is the permittivity of free space, εr is the relative permittivity of the material between the wires, A is the area of each wire, and d is the distance between the wires.