The formula for current is Amps = Watts/Volts. The lamp itself would draw 4.16 amps. Since the voltage of the lamp is 12 volts there is a internal transformer involved in the fixture itself. It doesn't matter what the input (primary) voltage to the transformer is, so long as it meets the manufacturer's specification as to the proper voltage to operate the fixture.
It would be pretty much undefined, since the filament of the halogen bulb would fail immediately then there would be an open circuit with no current draw. <<>> The formula for current is Amps = Watts/Volts. The lamp itself would draw 4.16 amps. Since the voltage of the lamp is 12 volts there is a internal transformer involved in the fixture itself. It doesn't matter what the input (primary) voltage to the transformer is, so long as it meets the manufacturer's specification as to the proper voltage to operate the fixture.
Since power is volts time amps, the current in a 60W lamp connected to 120V is 0.5A. Since a lamp is a resistive load, there is no need to consider power factor and phase angle, so that simplifies the explanation. ======================== Assuming this is an incandescent or halogen lamp (using a filament to make the light) there is a trick here: the resistance of a lamp filament varies with temperature and does not follow Ohm's law. The resistance will be much lower, thus the current will be much higher when the filament is cold, when the lamp is first connected. As the filament heats up, the resistance increases until it gets to a steady operating point of 0.5A. For a halogen lamp, the operating temperature is about 2800-3400K, so the R at room temperature is about 16 times lower than when hot... so when connected, the current is about 8A but drops rapidly. The current could be even higher if the lamp is in a cold environment. Non-halogen lamps operate at a lower temperature and would have a lower initial current--about 5A. And this all assumes the lamp is rated for 120V. If it is a 12V/60W lamp, the filament will probably break and create an arc, which may draw a very large current.
what is the diference between 12V 15A DC coil & 12V 10 amps DC coil
Yes, fluorescent lamps may be powered by DC but they need a DC lamp controller instead of an AC ballast and starter. The DC lamp controller is more complex. I have a 12V lantern with fluorescent lamp tubes.
The power dissipated by a circuit with a voltage of 12V and a current of 3A is 36W. Watts is Volts times Amps.
To calculate the current, you can use the formula: current (in amps) = power (in watts) / voltage (in volts). So, for a 50W halogen lamp operating at 12V, the current draw would be approximately 4.17 amps (50W / 12V = 4.17A).
1.67 Amps
It would be pretty much undefined, since the filament of the halogen bulb would fail immediately then there would be an open circuit with no current draw. <<>> The formula for current is Amps = Watts/Volts. The lamp itself would draw 4.16 amps. Since the voltage of the lamp is 12 volts there is a internal transformer involved in the fixture itself. It doesn't matter what the input (primary) voltage to the transformer is, so long as it meets the manufacturer's specification as to the proper voltage to operate the fixture.
Volts * Amps = Watts 12V * A = 150W A = 150W/12V A = 12.5
Yes you Can BUT you must get the Correct one. I found it is a 12v 35watt Halogen Lamp.
For a 100 watt 12 volt lamp, you should use a wire gauge size of at least 18 AWG to ensure it can handle the current without overheating. It's always best to refer to the manufacturer's recommendations for the specific lamp you are using.
To calculate the amperage, use the formula: Amps = Watts / Volts. In this case, 50 watts / 12 volts = 4.17 amps. So, a 50 watt 12V light will draw approximately 4.17 amps of current.
12V 5A = 12V 5000mA
160 amps at 12v.
160 amps at 12v.
The formula you are looking for is W = I x E.
To calculate the current you need to take theWatt rating of your welder and divide this by the voltage youhave setthe machine at- this gives the amperage. So for a 1440 watt welder running at 12v the current would be: 1440 watt/ 12v = 120 Amps