To reduce 12VDC to 7VDC you need a voltage divider in the ratio of 7/12, such as two series resistors of values 5KOhms and 7KOhms.
Of course, this "trite" answer (the resistor divider) depends on how much power you need to supply, and how much source to load current regulation ratio you need.
You might need to follow this up with an class C amplifier, compensating for the 0.6 volt drop across the base-emitter junction.
You might need an OP-Amp controlled emitter follower, with a zener reference.
For high current applications, you might even need a switching regulator.
Chat with our AI personalities
That depends on the application.
If it's 32 volts alternating current, you can use a transformer.
If it's 32 volts direct current you can use a solid state regulator.
Either way, if you want to go quick, dirty and cheap, you can just use a resistor in series with the load.
36 is to 12 as 18 is to 24.
12 volts
Since the equation for watts is: Volts * Amps = Watts that would mean 12 Volts * 1 Amp = 12 Watts
Yes. You can use a voltage divider. Say, for instance, one 1KOhm resistor in series with a 3KOhm resistor. Connect the 3k resistor to the 48 volts and connect the 1k resistor to ground. The 1k resistor will have 12 volts acress it. These resistors need to be at least 1 watt each as they are going to dissipate 0.576 watts and get warm. Now, if you attempt to pull power from the 1k resistor, note that regulation will be poor because the impedance of the load will go in parallel with the 1k resistor and change its value.
You are working with two different values. Watts is the product of amps times volts. W = A x V, as you can see if there is a value missing then there can be no answer given.