To determine the amperage of a 3-phase motor, you would need to know the voltage at which the motor operates. Assuming a standard voltage of 480 volts for industrial applications, a 25 hp 3-phase motor would typically draw around 30-32 amps. This calculation is based on the formula: Amps = (HP x 746) / (Voltage x Efficiency x Power Factor x √3).
The electrical code states that a 30 HP induction motor at 460 volts three phase will draw 40 amps. <<>> I = 33.34 AMPS IF EFF.= 95% AND P.F.= 85%
1.73*480*22
AWG #10 copper on a 30 amp breaker.
To calculate the required amperage for a 45 kW shredder operating at 415 volts in a three-phase system, you can use the formula: Amps = Power (Watts) / (Voltage × √3). For a 45 kW (or 45,000 watts) shredder, this would be: Amps = 45,000 / (415 × √3), which equals approximately 62.5 amps. Therefore, you would need around 62.5 amps for the shredder.
There is not enough information provided to answer. KVA is short for "Kilo Volt Amperes". That is, thousands of Volt Amps. In order to determine how many Amperes are flowing, you must know at what voltage it is operating. Amperes = 45,000 ÷ volts Bill Slugg
22 kw motor how much takes ampares with load
The electrical code states that a 30 HP induction motor at 460 volts three phase will draw 40 amps. <<>> I = 33.34 AMPS IF EFF.= 95% AND P.F.= 85%
481 amps if the load has a power factor of 1, but if the power factor is less than one (e.g. if it's a motor) you also have to divide by the power factor.
1.73*480*22
The formula you are looking for is Amps = kW x 1000/1.73 x E x pf. Use .84 for a power factor value.
To determine the running amps of a 45 kW motor, you would need to know the voltage at which it operates. You can use the formula: Amps = (kW x 1000) / (Volts x power factor). Once you have the voltage and power factor information, you can plug them into the formula to calculate the running amps.
The electrical code book states that a 40 HP 230 volt three phase motor draws 104 amps. For that motor the wire must be rated for 131 amps, Non time delay fuses at 300 amps, time delay fuses at 175 amps or a 250 amp circuit breaker. When calculating wire sizes and motor protection the motor's full load amperage should be taken from the motor's nameplate.
Read the specification plate on the motor to determine the amount of current that the motor uses, as well as the voltage and phase. Most likely, it will be a 3 phase motor, so you can't simply connect it to your house wiring, but without sufficient information, it is impossible to tell you all of the specifics. <<>> The code book rates the amperage of a three phase 40 HP motor by different voltages. at 200 volts - 120 amps, 230 volts - 104 amps, 460 volts - 52 amps and 575 volts - 52 amps. A breaker for a motor has to be sized to 250% of the motors full load amps. Also the wire size for a motor has to be 125% of the motor full load amps.
To calculate the amps drawn by an 18kW motor, you can use the formula: Amps = Power (Watts) / Voltage (Volts). Assuming a standard voltage of 120V, the motor would draw approximately 150Amps. Note that actual amps will depend on the specific voltage of the motor.
Need to know the voltage of the motor.
30 HP at 480 (3 Phase) - 746 multiplied by 30 = 22380 22380 divided by 480 (3 Phase) = 46.5 46.5 divided by 1.73 = 29.5AMPS Motor speed and efficiency may change the actual result. Always refer to the name plate data
depends what the source voltage isone horsepower equals to 746watts (assuming 100% efficiency)746 watts divided by voltage source equals current (amps)AnswerIn countries, such as the USA, where the horsepower is still used as a means of measuring power, it is always used to measure the output power of a motor.So, in order to determine the current drawn by the motor, you will first need to find out its input power. The input power is the output power divided by the machine's efficiency. Once you know its input power, then you can find its current by dividing the input power by the supply voltage. In practise, you will need to use a wattmeter to determine its input power.