A kw (kilowatt) is 1000 amps x volts. If you assume your one phase system has 120 volts, then divide by 120. Cheap, but close enough for most work, assume 100 volts, then each amp is a tenth of a kilowatt.
Assuming single phase voltage 220 Volts AC, the maximum current would be approximately 25 amps.
At 240v single phase it's 70.8 amps. If it runs on 2 wires plus ground, take the voltage rating of the equipment and divide that into the watts to get amps. At 480v 3 phase it's 25.8 amps. At 208v 3 phase it's 47.2 amps. <<>> There are zero amps in 14 kW. A voltage needs to be stated. I = W/E, Amps = Watts/Volts.
A kilowatt hour is the use of 1000 watts of power in 1 hour. The deicers should have a rating of a voltage such as 110 volts or 220 volts and a current of "X" amps. Multiply the voltage (in volts) times the current (in amps) and you will then know how much "power" in watts the deicer uses. My guess is you will see numbers such as 120 volts at 5 amps. Therefore 120 x 5 = 600 watts per hour or .6 kilowatts per hour.
There is not enough information provided to answer. KVA is short for "Kilo Volt Amperes". That is, thousands of Volt Amps. In order to determine how many Amperes are flowing, you must know at what voltage it is operating. Amperes = 45,000 ÷ volts Bill Slugg
A kw (kilowatt) is 1000 amps x volts. If you assume your one phase system has 120 volts, then divide by 120. Cheap, but close enough for most work, assume 100 volts, then each amp is a tenth of a kilowatt.
For a single phase circuit, the equation you are looking for is I = W/E. Amps = Watts/Volts.
The maximum single phase HP motor listed in the CEC is 10 HP. At 115 volts 100 amps and 230 volts 50 amps.
Amps can not give you a kilowatt with out a voltage being applied to the question. Watts = Amps x Volts. Amps = 1000/ Volts.
watts = volts x amps kilowatt = 1000 watts
watts are equal to amps times volts.
The equation that you are looking for is Amps = Watts/Volts. There are 6000 watts in 6kW.
if it's single-phase, 25,000 divided by 480.
The formula you are looking for is I = W/E. Amps = Watts/Volts.
A 18000 watt generator supplying power at 240 volts would supply 75 amps (18000 watts รท 240 volts = 75 amps).
For single phase,kva=voltage(volts)xcurrent(amps)/1000 For,three phase,kva=1.732xvoltsxamps/1000
To calculate the amperage, you can use the formula: Amperes = Watts / Volts. So, for a 500 kW system at 240 volts, the amperage would be 2083.33 Amps.