There is one part of the question missing. To find an answer the kW of the heater must be stated. Then the equations used are, to change kW to watts, Kw/1000 = watts. Once that is found then use, I = W/E, Amps = Watts/Volts. This will give you the value in amperage of the heater.
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The formula you are looking for is I = W/E. Amps = Watts/ voltage. Amps = 1000/240 = 4.1 amps. The wire for this circuit is a #14 wire.
A kw (kilowatt) is 1000 amps x volts. If you assume your one phase system has 120 volts, then divide by 120. Cheap, but close enough for most work, assume 100 volts, then each amp is a tenth of a kilowatt.
Assuming single phase voltage 220 Volts AC, the maximum current would be approximately 25 amps.
At 240v single phase it's 70.8 amps. If it runs on 2 wires plus ground, take the voltage rating of the equipment and divide that into the watts to get amps. At 480v 3 phase it's 25.8 amps. At 208v 3 phase it's 47.2 amps. <<>> There are zero amps in 14 kW. A voltage needs to be stated. I = W/E, Amps = Watts/Volts.
A kilowatt hour is the use of 1000 watts of power in 1 hour. The deicers should have a rating of a voltage such as 110 volts or 220 volts and a current of "X" amps. Multiply the voltage (in volts) times the current (in amps) and you will then know how much "power" in watts the deicer uses. My guess is you will see numbers such as 120 volts at 5 amps. Therefore 120 x 5 = 600 watts per hour or .6 kilowatts per hour.
There is not enough information provided to answer. KVA is short for "Kilo Volt Amperes". That is, thousands of Volt Amps. In order to determine how many Amperes are flowing, you must know at what voltage it is operating. Amperes = 45,000 ÷ volts Bill Slugg