A sauna heating element is a resistive load. The equation that you are looking for is Amps = Watts/Volts = 8000/220 = 36 amps.
A #8 copper conductor with an insulation rating of 90 degrees C is rated at 55 amps. This will be fed with 40 amp two pole breaker.
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a 220 volt, 3200 watt oven will draw under 15 amps, so yes a 2o amp breaker will work.
The smallest size breaker is a 15 amp and with a #14 wire which has a capacity for 15 amps and a 120 volt source, this combination will give you the capacity up to 1800 watts. W = A x V, 120 x 15 = 1800.
about 4800 watt but should not use it 100% so to be safe 4000 watt (80%)
50 watt equals less than 1/2 amp current flow at 120 volts so you can have 30 light on a 15amp breaker or 40 on a twenty amp breaker.
10000 watts / 220 volts = 45.4545 amperes