A 5 kW generator would turn it over but if the full 30 hp of mechanical power is needed, that would require about 30 kW of electric power from the generator.
a: there is no calculated load for the range. This 16 kw is the maximum that this particular range can safely use any thing less is OK.
200 hp requires about 149kW
I would look up your boiler specs or maybe contact that boiler brand and they would be able to help you because your question can be for many different situations.
Check the nameplate rating on the door or door frame of your washer, it should tell you the amp rating or the kw rating of the machine. If it only has the KW rating of the machine, simply divide the KW rating by the voltage of the receptacle and it'll give you the current (ampere) rating. Typically, a modern washing machine will draw approximately 7-12 amps. However, anticipate a higher amperage when starting the machine as the machine will draw 1.5X the rated current to start the machine (starting current). Regardless of the amp rating, the NFPA-70 (National Electrical Code) requiresa 20 Amp fuse or circuit breaker; and the circuit for the washing machine must be on its own, dedicated circuit.
That depends on the KW rating . You should consult a qualified electrician
To convert kilowatts (KW) to boiler horsepower (BHP), divide the KW value by 9.81. Therefore, 45 KW is equal to approximately 4.59 boiler horsepower.
That depends on the KW rating . You should consult a qualified electrician
The electric unit rating refers to the amount of electricity consumed or generated by an electrical appliance or device. It is typically measured in watts (W) or kilowatts (kW), representing the rate of energy transfer. The higher the electric unit rating, the more power the device consumes or generates.
The cooker gives its power rating at 2.3 Kw, which appears similar to other kitchen appliances.
yes
The kW rating of a transformer can be calculated by multiplying the kVA rating by the power factor. For example, if the power factor is 0.8, then the kW rating of a 100 kVA transformer would be 80 kW. You can also use the formula: kW = kVA x power factor.
Depends upon the Kw rating of the generator. The higher the Kw rating the more fuel will be used.
kva*cos(phase angle)
the given kw Divide by the your voltage
If the town has natural gas for heating, then the power needed per household is between 5 kW and 10 kW. If only electric heat is available, then the combination of electric resistance (auxiliary - from 7 to 10 kW for small residential units) heating, combined with electric clothes dryer (from 2 to 5 kW), electric water heater (from 2.5 to 7.5 kW), and stove (5 kW to 7.5 kW) totaling a min of 15 kW to a max of 20 kW. That would put the max power requirements between 5,000 kW and 10,000 kW. As a matter of reality, a diversity factor of .6 to .7 would reduce the max power to 3,500 kW and 7,000 kW.
That depends on how long the 1 kW is applied. Please note that kW is a unit of power, not a unit of energy.In general, 1 kW of electrical energy can be converted into 1 kW of heat - if used in a heater. With a heat pump, 1 kW of electrical energy can, in fact, pump several kW of heat energy.