To answer this question a voltage needs to be stated. Wire is sized by the amount of amperage the load takes. W = Amps x Volts. Amps = 650/ volts.
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A 350 MCM copper conductor with an insulation factor of 75 or 90 degree C is rated at 310 and 325 respectively. So depending on the insulation of the wire that is used, a parallel wire configuration will give you a total of 620 at 75 degrees C or 650 at 90 degrees C.
It's going to take a whopper of a wire to run a 20 amps 650 feet. I'd feel more comfortable if a journeyman electrician would come by to access my answer. But, my calculations show it would take 4 AWG wire to do it. If you want you could run two 7 AWG wires in parallel.
Yes, as long as the bar fridge wattage is less than 650 W
70mm 4core copper cable
The question isn't the number of amps total on your branch circuits, but rather, what your MAIN breaker(s) are rated at. This will determine what size of generator you will need. And be certain that the generator is 3-phase. <<>> The formula you are looking for is Amps = kva x 1000/1.73 x voltage.