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1 22 333 4444 Any text editor is usable for that.
1 22 333 4444 But if your question was about printing this sequence for nth term, then:
#include
#include
void main()
{
int n,i,j;
clrscr();
printf("Enter the last limit\n");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
for(j=1;j<=i;j++)
{
printf("%d",i);
}
}scanf(" ");
getch();
}
Hey look the above code will print out the series up-to the nth limit which is inputed from the user.
If u use only puts() then u have limitation, i.e. u can't print the series up-to nth term in a normal way and generally this program appears in series up-to nth term.
Thank u.
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Taigafor (int i=1;i<6;i++) {
for (int k=0;k<i;k++)
print(i);
printnewline();
}
In PhP you would write something lime this;
<html>
<head>
<title>Exercise-2>
</head>
<body>
<?
{
for ($count =1; $count <10; $count++)
{
for ($newcount =0; $newcount<$count; $newcount++)
{
$answer = "$count<BR>";
{
echo "$answer";
}
}
}
}
?>
</body>
</html>
#include<stdio.h>
int main()
{
int i=1,j,n;
printf("enter how many values\n"); //take input as "6"//
scanf("%d",&n);
while(n!=i)
{
for(j=1;j<=i;j++)
printf("%d",i);
printf(" ");
i++;
}
return 0;
}
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1 22 333 4444 55555 i need a java program that generates a triangle with these numbers?
Implement this method: public static void makeTriangle(int limit) { int count = 0; for(int i = 1; i <= limit; i++) { count = i; while(count > 0) { System.out.print(i); count--; } System.out.println(); } }
C program to print 1 12 123 1234?
#include <stdio.h> int main (void) { puts ("1 22 333 4444 55555"); return 0; }
C program to print the format 4 1 44 11 444 111 4444 1111 000000000 444444 3333 22 1?
#include <stdio.h> int main (void) { puts ("4 1 44 11 444 111 4444 1111 000000000 444444 3333 22 1"); return 0; }
Write a c sharp program to print 1 22 333 4444 55555 as right angle trianglr?
using System;namespace RightAngleTraingle{class Program{static void Main(string[] args){for (int x = 1; x
How would you write a c program using nested loop that output the values are 1 22 333 4444 55555?
The solution is two use a nested for loop: int startingNum = 1; int maxNum = 10; for(int currentNum = startingNum; currentNum <= maxNum; currentNum++) { for(int j = 0; j < currentNum; j++) { printf("%d", currentNum); } printf("\n"); }
How would you write a C program loop that outputs the values 4444 333 22 1?
int i = 4;while (i>0) { for (int n=0; n<i; ++n) { printf ("%d", i); } printf (" "); } printf ("\n");
What is the sequence of 122333444455555?
Each digit is repeated the number of times equal to its value. 1 22 333 4444 55555 666666 7777777 88888888 999999999
How do you write 55555 4444 333 22 1 in php?
This is one of possible solutions:
What is 4444 using exponents?
22 x 11 x 101 = 4444
1 22 333 4444 55555 i need a java program that generates a triangle with these numbers?
Implement this method: public static void makeTriangle(int limit) { int count = 0; for(int i = 1; i <= limit; i++) { count = i; while(count > 0) { System.out.print(i); count--; } System.out.println(); } }
C program to print 1 12 123 1234?
#include <stdio.h> int main (void) { puts ("1 22 333 4444 55555"); return 0; }
What is the program to print 1 22 333 4444?
#include<iostream> int main (void) { std::cout << "1 22 333 444\n"; } To produce the text programmatically: #include<iostream> int main (void) { for (int num=1; num<=4; ++num) { // the number to be printed for (int rep=1; rep<=num; ++rep) { // the repetitions of that number std::cout << num; } std::cout << ' '; // space } std::cout << '\n'; // new line }
What is 333-22?
355
C program to print the format 4 1 44 11 444 111 4444 1111 000000000 444444 3333 22 1?
#include <stdio.h> int main (void) { puts ("4 1 44 11 444 111 4444 1111 000000000 444444 3333 22 1"); return 0; }
What are numbers like 22 and 333?
22 and 333 are composite numbers.
Write a c sharp program to print 1 22 333 4444 55555 as right angle trianglr?
using System;namespace RightAngleTraingle{class Program{static void Main(string[] args){for (int x = 1; x
What is the product of 22 and 2?
the product of 22 by 2 is 4444
