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def digits(x):
""" Return amount of digits of x. """
y = math.log10(x)
if y % 1 0:
return int(y)
else:
return int(math.floor(y) + 1)

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15y ago
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15y ago

for (revn=0; n!=0; n/=10) revn = 10*revn + n%10;

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Q: Algorithm to count the digits in a given number?
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How do you write an assembly language program to count the number of ones in a given byte?

1. Find algorithm.2. Implement it.Hint: if a non-zero N number has K 1-bits, then (N AND N-1) has K-1 1-bits.


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Related questions

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To assess the number of significant digits in a number, you first have to find the greatest non-zero digit. In this case it is the first five which represent 500. The next step is to simply count how many digits there are after this number. In this case, there are 4 more digits. Thus the number 500.95 has been given to 5 significant digits.


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How do you write an assembly language program to count the number of ones in a given byte?

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Write algorithm to find the sum of the digits in a given 4 digit no ex- no is 8516 then 8 5 1 6?

I cannot do your homework, if you cannot explain it properly.