BF =( Tdb,out - Tcoil )/(Tdb,in - Tcoil)
Source: MERM for the PE Exam - Michael Lindeburg, PE
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It is due to presence of form factor(Kf) in the emf equation of Alternators and transformers. Value of form factor is 1.11.
The formula is: current (in amps) = power (in watts) , divided by (240 times the power factor). The power factor is 1 for incandescent light or heaters, otherwise it can be assumed to be 0.75 for other loads.
Power factor is defined as the ratio of real power over total power. Total power is the vector sum of real and reactive power.
{| |- | capacitance of the capacitor is mentioned in KVAR. Formula : KVAR = KW*tan@ FOR tan@, First note the power factor & KW without connecting capacitor. The noted power factor is in cos@.Convert the cos@ value in tan@. for ex. If power factor is 0.6, KW = 200 cos@ = 0.6 cos-1 (0.6) = 53.1 tan (53.1) = 1.333 200*1.333 = 266.6 KVAR if you use 266 KVAR capacitor, Then the power factor improves to unity (1.000). |}
Yes, sort of. At least for DC, that's correct, since P = I x V (power = current x voltage). In the case of AC, the correct formula is: P = I x V x (power factor) In many practical situations, the power factor is close to 1, and can therefore be ignored.