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You basically write a nested for loop (one for within another one), to copy the elements of the matrix to a new matrix.
Automated proofs are a complicated subject. If you are not an expert on the subject, all you can hope for is to write a program where you can input a sample matrix (or that randomly generates one), and verifies the proposition for this particular case. If the proposition is confirmed in several cases, this makes the proposition plausible, but is by no means a formal proof.Better try to prove it without writing any program.Note: it is not even true; it is the inverse of the matrix which gives identity when is multiplied with the original matrix.
Linkage relates to how much one module in a program must rely on another
/*Program to Copy one string to another using pointer.*/#include#includemain(){char a[80],b[80],*pa,*pb;int i=0;clrscr();printf("Given first string ");scanf("%s",a);pa=&a[0];pb=&b[0];while(*pa!='\0'){*pb=*pa;pa++;pb++;}*pb='\0';printf("\nCopied string is");puts(b);}
Provided both matrices are mutable, two matrices A and B can be swapped like any other two items: create temporary storage to store a copy of A, then assign B to A, and finally assign the temporary copy of the previous version of A to B. Note that in the C programming language, matrices cannot be assigned to each as such. One implementation of this algorithm might operate on the basis of references (pointers), and can thus swap two matrix references by swapping two pointers in the manner detailed above. Implementations wishing to actually transfer the data held in one matrix to another would use a library function such as memcpy() to transfer data.