#include<stdio.h>
#include<conio.h>
main()
{
int i,j,n;
printf(" Enter the number upto which you want to find prime number ");
scanf("%d",&n);
printf("\n");
for(i=2;i<=n;i++)
{
for(j=2;j<=i-1;j++)
if(i%j==0)
break;
if(i==j) printf("\n\t%d",i);
}
getch();
}
//for example if u want to find Prime number between 1 to 100 enter 100..
// u will get prime number between 1 to 100
//tested in bloodshed dev c++
To write a C program to find prime numbers between 1 to 500, you can use a nested loop structure. In the outer loop, iterate from 2 to 500, and in the inner loop, check if the number is divisible by any number from 2 to the square root of the number. If it is not divisible by any number other than 1 and itself, then it is a prime number. Print out all prime numbers found within the specified range. Remember to include necessary header files, such as <stdio.h>, and use appropriate logic to implement the program efficiently.
Write a program to find the number and sum of all integers from 100 to 300 that are divisible by 11
It should not be even (except for 2), and must not be dividable with any odd number between 3 and its square-root.
flow t prime numberchar
write a c++ program to convert binary number to decimal number by using while statement
10 input "enter a no."; n 20 for i = 1 to n 30 if n mod i = 0 then c = c +1 40 next i 50 if c = 2 then print "prime number" else print "not a prime number" 60 end
Yes, do write, or if you're too lazy to your homework, use google.
see the program
To get all tutorials of "c programming" Reference:cprogramming-bd.com/c_page2.aspx# prime number
Since there is an infinite set of prime numbers the answer would be infinity.
By learning how to program on C+.
#include<iostream.h> #include<conio.h> int main() { int i,n; clrscr(); cout<<"PROGRAM TO CHECK IF THE NUMBER IS PRIME OR NOT:"<<endl; cout<<"Enter a number:"; cin>>n; for(int i=2;i<n;i++) { if(n%i==0) cout<<"\nTHE NUMBER IS COMPOSITE"<<endl; else cout<<"\nTHE NUMBER IS PRIME"<<endl; } return 0; }
To write a C program to find prime numbers between 1 to 500, you can use a nested loop structure. In the outer loop, iterate from 2 to 500, and in the inner loop, check if the number is divisible by any number from 2 to the square root of the number. If it is not divisible by any number other than 1 and itself, then it is a prime number. Print out all prime numbers found within the specified range. Remember to include necessary header files, such as <stdio.h>, and use appropriate logic to implement the program efficiently.
find the program in c-pgms.blogspot.com
Write a program to find the number and sum of all integers from 100 to 300 that are divisible by 11
#include<stdio.h> #include<conio.h> void main() { int n,i; clrscr(); printf("Enter a Number:"); scanf("%d",&n); printf("\n\nPrime Factors of %d is: ",n); for(i=2;i<=n;i++) { if(n%i==0) { printf("%d,",i); n=n/i; i--; if(n==1) break; } } getche(); } this program will find the prime factors of a given numbe any assistance mail at :- devilllcreature@yahoo.com thank you
#include<iostream.h> #include<conio.h> void prime(int n) { clrscr(); int num; cout<<"enter the numbers"<<endl; cin>>num; prime(num); getch(); } void prime(int n) { int prime=1,i; for(i=2;i<=n/2;i++) if(n%i==1) prime=0; if(prime==1) cout<<"the number"<<n>>"is prime"; else cout<<"the number"<<n<<"is not prime"; }