Draw a flowchart to find the even numbers from 1 to 100?

Answer 1

To create a flowchart to find even numbers from 1 to 100, you would start with an oval shape labeled "Start." Then, use a process symbol with a decision diamond to check if the number is divisible by 2. If it is, move to a rectangle labeled "Output" to display the even number. If not, return to the decision diamond. Continue this loop until you reach 100, then end with an oval labeled "End." This flowchart will systematically identify and output all even numbers between 1 and 100.

Answer 2

To draw a flowchart to find even numbers from 1 to 100, begin with a box labeled start. Assign a color to even numbers and a color to odd numbers. Beginning at the start box, make an arrow down and insert the number "1" into the box, continue adding arrows and numbers until you reach 100. If you used pink for even numbers and blue for odd numbers, each number in the list that is divisible by 2 will be colored in pink, and all the rest will be colored in blue.

Answer 3

For this first the given no. is initialise with 0 suppose 'n' is a given no. and as we all know that even no's r those no's which r completely divided by 2 so here we r applying this condition.NOTE:Symbols u can draw urself.

1. Draw a circle and write START
2. Draw a rectangle box for initialization and write n=0.
3. Draw a gm symbol for reading the no. 'n'.
4. After this draw a decision box i.e diamond shape and write ls(n%2==0)? then make two lines attached to the decision box i.e for true or false.

5. If condition is true then print no. is even,n otherwise print no. is not even ,n and these statements should be in gm box.

6. After this again draw a circle and write STOP.

NOTE:Here % sign is a modulous operator which stores the remainder.

Read more: How_can_you_draw_a_flow_chart_to_find_out_that_given_number_is_odd_or_even

Answer 4

One if statement:

If the number is divisible by two with no remained then the number is even

else it is odd.

Another way:

x = any whole number

if x%2 = 0 then the number is even, else it's odd, since the % or "mod" sign repeatedly divides x by 2 until it has a remainder.

Answer 5

For this first the given no. is initialise with 0 suppose 'n' is a given no. and as we all know that even no's r those no's which r completely divided by 2 so here we r applying this condition.NOTE:Symbols u can draw urself.

1. Draw a circle and write START
2. Draw a rectangle box for initialization and write n=0.
3. Draw a gm symbol for reading the no. 'n'.
4. After this draw a decision box i.e diamond shape and write ls(n%2==0)? then make two lines attached to the decision box i.e for true or false.

5. If condition is true then print no. is even,notherwise print no. is not even ,n and these statements should be in gm box.

6. After this again draw a circle and write STOP.

NOTE:Here % sign is a modulous operator which stores the remainder.

Answer 6

This is a text-based Wiki. We cannot draw flowcharts here.

To determine if any integer is odd or even, use the modus operator (%) with an r-value of 2 (the modus operator dives the l-value by the r-value and returns the remainder of the division). The result can only ever be 0 or 1. If it is 0, the integer is even, otherwise it is odd.

E.g.,

int x = rand()%100 + 1; // pick a random number from 1 to 100

if( x%2 )

//... x is odd

else

//...x is even

Answer 7

The only criteria for evenness is divisibility by 2, so that's all you have to check for.

So the flowchart would look like this:

start -> is the number divisible by 2? (yes)-> it is even.

(no) -> it is odd.

Answer 8

Flowchart to determine if a given number is odd or even:

START|Enter a whole number|Divide the number by 2|NO<---Is the remainder zero?--->YES||Number is oddNumber is even||--->END<---

Answer 9

An algorithm to find the even numbers between 1 and 100, in C# //This will hold the results
List evenList = new List();
for (int i = 1; i

Answer 10

sum := 100 * (2+200) / 2;plzzzz some buddy solved it i need help soon