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∙ 14y agoThe figure 1.73 is the results of the square root of 3. 1.73 is used in three phase calculations. The number is also used on three phase four wire systems. To find the coil voltages of a wye system 1.73 is divided by the phase voltage. An example, three phase 480 wye system. 480/1.73 = 277 volts
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∙ 14y agovolts times amps equal watts, or 550 lbs per sec equals 1 horse power.
Specifically, Volts and Amps would be called VA or volt amps, as in the rating of a transformer, but it is loosely referred to as Watts. In DC theory, Volts mulitplied by Amps equals Watts. In AC theory, that same equation exists but it includes power factor. If the power factor given is 1 (100%), then Volts mulitplied by Amps multiplied by Power Factor of 1 equals your Watts.
The formula you are looking for is, kW x 1000/1.73 x volts x pf (power factor).
1 HP is 746 watts in principle. The power is in watts, and the power is the volts times the amps. For an AC motor the power is the volts times the amps times the power factor times a factor that depends on the power-conversion efficiency of the motor.
You didn't define "importance" so it is hard to tell. They are all related by the formula Watts = Volts x Power Factor. Power Factor varies from zero to one. One thing that is often done in an application is to try to reduce the current and proportionally increase the voltage to obtain the needed wattage. That is why most electric stoves run at 240 volts rather than 120 volts, because 1/2 the current is required at the higher voltage; and you can use smaller wire and connect to a lower amperage breaker.
In DC, power equals voltage x current. In AC, power equals voltage x current x power factor. The power factor is an adimensional constant, and in common circuits it is often close to 1.
volts times amps equal watts, or 550 lbs per sec equals 1 horse power.
W = Amps times Volts. A = W/V, A = 300/120 = 2.5 amps
In an AC system the power is often less than the volts times the amps. The full formula is watts = volts times amps times power-factor. Some bulbs have a power-factor as low as 0.5.
To find the current, use the formula: Power (W) = Voltage (V) x Current (A). Rearrange the formula to solve for current: Current (A) = Power (W) / Voltage (V). Therefore, 160 watts divided by 120 volts equals 1.33 Amps.
746 Watts per horsepower / 480 volts x power factor x efficiency x 1.73 = amps assuming that the motor is three phase. 746 x 60 =44760 watts divided by 480 x 1.73 = 53.9 amps ( If the pf and eff. information is not known this will put you in the ball park)
Specifically, Volts and Amps would be called VA or volt amps, as in the rating of a transformer, but it is loosely referred to as Watts. In DC theory, Volts mulitplied by Amps equals Watts. In AC theory, that same equation exists but it includes power factor. If the power factor given is 1 (100%), then Volts mulitplied by Amps multiplied by Power Factor of 1 equals your Watts.
Watts = Amps x Volts x Power Factor. Power Factor = 1 for resistive loads and gets smaller for inductive loads like motors. Assuming home voltage of 120 Volts and a PF = 1 your answer is 400/120 = 3.33 amps.
The formula you are looking for is, kW x 1000/1.73 x volts x pf (power factor).
Current can be calculated by dividing the power (in watts) by the voltage. In this case, 350 watts divided by 220 volts equals a current of approximately 1.59 amps.
Watts = Amps x Volts x Power Factor Maximum value of PF is 1 for a resistive load. If you have 120 volts and a PF = 1, then amps = 10.
To calculate the amperage, you can use the formula: Amperage = Power (watts) / Voltage (volts). In this case, for a 2.2kW kettle at 240 volts, the amperage would be 9.17 amps.