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How can you convert binary number into decimal number using g plus plus compiler?
The following code will convert any number in any base to any other base, from binary to hexadecimal, and everything inbetween.
#include<iostream>
#include<string>
#include<sstream>
typedef unsigned long long ull;
typedef unsigned long ul;
const std::string symbols="0123456789abcdef";
std::string inputvalue(ul base)
{
using namespace std;
string value;
while(1)
{
cout<<"Enter a positive value : ";
string s;
getline(cin,s);
if(s.size())
{
for(string::iterator i=s.begin();i!=s.end();++i)
if(*i>='A' && *i<='Z')
*i+=32;
string actual = symbols.substr(0,base);
if(s.find_first_not_of(actual)!=string::npos)
{
cout<<"The value you entered is invalid for the base.\n"
<<"Please enter another value.\n"<<endl;
continue;
}
value=s;
break;
}
}
return(value);
}
ul inputbase(std::string prompt)
{
using namespace std;
ul result=0, min=2, max=16;
while(1)
{
cout<<prompt.c_str()<<" ["<<min<<".."<<max<<"] : ";
string s;
getline(cin,s);
if(s.size())
result=stoul(s,0,10);
if(result<min result>max)
cout<<"The base must be in the range "
<<min<<".."<<max<<"\n"
<<"Please enter another base.\n"<<endl;
else
break;
}
return(result);
}
ull base2dec(std::string value,ul base)
{
ull col=1, num=0;
for(std::string::reverse_iterator i=value.rbegin(); i!=value.rend(); ++i)
{
num+=symbols.find(*i,0)*col;
col*=base;
}
return(num);
}
std::string dec2base(ull dec,ul base)
{
using namespace std;
int len=1;
ull tmp=dec;
while(tmp/=base)
++len;
string value("0",len);
while(dec)
{
value[--len]=symbols[dec%base];
dec/=base;
}
return(value);
}
int main()
{
using namespace std;
ul base=inputbase("Enter the base of the value");
string value=inputvalue(base);
ul newbase=inputbase("Enter the base to convert to");
value=dec2base(base2dec(value,base),newbase);
cout<<"New value:\t"<<value.c_str()<<endl;
return(0);
}
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How do you write a c program to convert binary to decimal by using while statement?
write a c++ program to convert binary number to decimal number by using while statement
