You can do this with a simple for loop counting through the array and increasing a tally each time you sought number is hit.:
tally = 0
for each element in the array {
if this element has the value we want{
tally = tally + 1
}
}
output the taly
In PHP for example, this could be done like so:
$tally = 0;
foreach($foo as $bar){
if($bar == $value_sought) $tally++;
}
echo $tally;
where "$foo" is the array you're serching and $value_sought is the number you're looking for.
Using the function "count". <?php $foo = array("John", "Jacob", "Jingleheimer", "Schmidt"); echo count($foo); // <-- outputs the number 4 ?>
<pre> sub average { @_ 1 or die ('Sub usage: $median = median(\@array);'); my ($array_ref) = @_; my $count = scalar @$array_ref; # Sort a COPY of the array, leaving the original untouched my @array = sort { $a <=> $b } @$array_ref; if ($count % 2) { return $array[int($count/2)]; } else { return ($array[$count/2] + $array[$count/2 - 1]) / 2; } } </pre>
You add up all the array elements, then divide by the number of elements. You can use a nested for() loop in Java; inside the inner for() loop, you can both increase a counter (to count how many elements there are), and add to a "sum" variable.
Basically in C language string is NULL (0x00) byte ending char array. So in order to find out the length of the string you need to count all elements in array until you reach NULL. But that is what strlen does. There are two links with information about strlen implementation and null-terminated strings.
#include<stdio.h> #include<conio.h> void main() { int a[10],i,j,k; int count=1,num[10],pos=0; clrscr(); printf("Enter the Array Element "); for(i=0;i<10;i++) { scanf("%d",&a[i]) ; }//close the for loop for(i=0;i<10;i++) { count=1,pos++; for(j=0;j<10;j++) { if(a[i]==a[j]) { for(k=j;k<10;j++) a[k]=a[k+1] }//close the if count++; }//close the for loop num[pos] = count; }//close the for loop for(i=0;i<pos;i++) printf("Repeted Number of IN Arrary %d",num[i]); }//close the main
Using the function "count". <?php $foo = array("John", "Jacob", "Jingleheimer", "Schmidt"); echo count($foo); // <-- outputs the number 4 ?>
A program which is used to count the number of numbers in an array using a 8085 microprocessor is known as a assembly language program.
<pre> sub average { @_ 1 or die ('Sub usage: $median = median(\@array);'); my ($array_ref) = @_; my $count = scalar @$array_ref; # Sort a COPY of the array, leaving the original untouched my @array = sort { $a <=> $b } @$array_ref; if ($count % 2) { return $array[int($count/2)]; } else { return ($array[$count/2] + $array[$count/2 - 1]) / 2; } } </pre>
There is no such number. If we could count to any particular number, then we can always count to the next one. And then the next. And so on.
Both could be correct it depends on the situation. If you could count the stars how many so you think there are? Count the number of stars you can see out the window.
To find the size of an array in PHP you can either use the count() function or the sizeof() function as they will produce the same result. <?php $array = array(1, 2, 3, 4, 5, 6, 7); echo count($array); // outputs 7 echo sizeof($array); // outputs 7 ?>
build an array of vowels then do a foreach on the array and then explode the string on the array value and the answer is -1 of the result
too many to count
abhimanyu
To count the number of elements in a compound, you can identify the different elements present by looking at the chemical formula. Each element is represented by a unique symbol (e.g., H for hydrogen, O for oxygen). Count the number of unique elements present in the compound to determine the total number of elements.
To find out how many results there are in a PHP array all you need to do is use the function count() like I have shown you in the example below.
If all elements of the array are in use then the last record is referred to as MAX-1. If you are using a count variable to remember how far into the array you are using then this variable will keep track of the last allocated value in the array.