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The input power, that is, the power required to operate the pump should be stated in Hp (horsepower) on the pump's nameplate. It can also be calculated by the 3-phase power equation:

P(in Hp) = VI(1.73) = Rated Voltage x Rated Current x 1.73/ %Efficiency

If this is a consumer grade pump that operates on 120Vac, then the equation becomes P = VI, simply multiply the operating voltage, 120 x current (which is the number followed by the letter "A".

The nameplate might look something like this:

___________________

| |

| Make: xxxxxx |

| Model: xxxxxx |

| Volt: xxx |

| Amp: xxx |

| %Eff: xx |

| |

|__________________|

The output power, which really isn't technically power, but rated in Gpm (gallons per minute), or capacity should also be on the nameplate. If you have the make, model, and (not necessarily needed) the serial number (also on the nameplate) you could call the manufacturer's customer service dept. As an application engineer, I have contacted countless manufacturer's service dept's for assistance. It is now big deal to them, they will be happy to answer your questions.

If it is the absorbed power of the pump to allow you to select a suitable motor then this is a function of the generated head, flowrate, specific gravity of the fluid and the pump efficency from the OEM / pump performance curve.

For those of us not in the US or using English units then the power can also be specified in kW.

In simple terms Power (kW) = Flow x Head x SG / (367 x Effy)

Where Flow is in cubic metres / hour, head is in metre, Specific Gravity (SG) being a dimensionless unit - cold clean water SG = 1 and efficency as a % from the curve or other means.

If you are trying to evalaute wire to water efficency then you can set efficency in the equation above to 1 and then ratio the input (measured power) to output power (calculated water horse power) to obtain the overall efficency.

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11y ago

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