// declare a function
int* function(int, int);
or
int* (function)(int, int);
// declare a pointer to a function
int* (*pointer_to_function)(int, int);
whatever the variables we declare in function signature to receive the arguments at the calling that are known as parameters.. e.g. int sum(int a,int b); here a & b are known as parameters.....
yes, we can not declare a function in the body of another function. but if we declare a function in the body of another function then we can call that very function only in that particular function in which it is declared; and that declared function is not known to other functions present in your programme. So if a function is required in almost all functions of your programme so you must declare it outside the main function i.e in the beginning of your programme.
Please ask just one question at a time!Question 1:How do you declare an array of three pointers to chars?How do you declare an array of three char pointers?Note: both of these questions are merely alternative wordings for the same question.Answer 1:char * a[3];Question 2:How do you declare a pointer to an array of three chars?Answer 2:char a[3]; // an array of three charschar * p = a; // a pointer to an array of three charsQuestion 3:How do you declare a pointer to a function which receives an int pointer?Answer 3:#include // some functions we can point at:void func_1(int * p){}void func_2(int * p){}// note: all functions we wish to point at with the same// pointer must have the same signature.int main(){int* p = NULL; // instantiate an int pointervoid (*pFunc) (int*); // declare a function pointerpFunc = func_1; // point to func_1pFunc(p); // call func_1 via function pointerpFunc = func_2; // point to func_2pFunc(p); // call func_2 via function pointerreturn(0);}Note that the brackets in the function pointer declaration are required. If you omit them, you will end up with a standard function declaration that returns a pointer to void, resulting in a compiler error.
You need to declare it first. A function declaration is made of three parts: The kind of data the function returns, I.E. void, int, etc. The name of the function, I.E. helloWorld. The list of parameters in parentheses, I.E. (A as int, B as char) For an example, here it is: void helloWorld(); Now, to put something inside the function, you can write the following: void helloWorld() { printf("Hello world!"); }
Default arguments are function parameters for which a default value is implied when not explicitly stated. int foo(int x, int base=10 ) { return( x%base); } The above function assumes 'base' is 10 unless you specify otherwise when making the call. Thus calling foo(15) will return 5, as will foo(5,10), but foo(15,16) will return 15. Note that default parameters must appear after all non-default parameters in a function declaration. Once you specify a default parameter, all other parameters that follow must also have default values. Note also that when the definition of a function is split from its declaration, only the declaration should declare the default parameters: // Declaration: int foo(int x, int base=10 ); // Definition: int foo(int x, int base ) { return( x%base); }
whatever the variables we declare in function signature to receive the arguments at the calling that are known as parameters.. e.g. int sum(int a,int b); here a & b are known as parameters.....
*Return variable type* *Function Name* (*Function parameters*) For example: int MyFunction (x,y)
In C, there is no default value for formal parameters. In C++, there can be, but the value is whatever you declare in the function declaration.
whatever the variables we declare in function signature to receive the arguments at the calling that are known as parameters.. e.g. int sum(int a,int b); here a & b are known as parameters.....
char *p="ragav"
typedef float (*pt_func)(int, int); pt_func arr[3];another way:float (*pt_func[3])(int, int);
*function();this declares a pointer function!
yes, we can not declare a function in the body of another function. but if we declare a function in the body of another function then we can call that very function only in that particular function in which it is declared; and that declared function is not known to other functions present in your programme. So if a function is required in almost all functions of your programme so you must declare it outside the main function i.e in the beginning of your programme.
Please ask just one question at a time!Question 1:How do you declare an array of three pointers to chars?How do you declare an array of three char pointers?Note: both of these questions are merely alternative wordings for the same question.Answer 1:char * a[3];Question 2:How do you declare a pointer to an array of three chars?Answer 2:char a[3]; // an array of three charschar * p = a; // a pointer to an array of three charsQuestion 3:How do you declare a pointer to a function which receives an int pointer?Answer 3:#include // some functions we can point at:void func_1(int * p){}void func_2(int * p){}// note: all functions we wish to point at with the same// pointer must have the same signature.int main(){int* p = NULL; // instantiate an int pointervoid (*pFunc) (int*); // declare a function pointerpFunc = func_1; // point to func_1pFunc(p); // call func_1 via function pointerpFunc = func_2; // point to func_2pFunc(p); // call func_2 via function pointerreturn(0);}Note that the brackets in the function pointer declaration are required. If you omit them, you will end up with a standard function declaration that returns a pointer to void, resulting in a compiler error.
yes
You need to declare it first. A function declaration is made of three parts: The kind of data the function returns, I.E. void, int, etc. The name of the function, I.E. helloWorld. The list of parameters in parentheses, I.E. (A as int, B as char) For an example, here it is: void helloWorld(); Now, to put something inside the function, you can write the following: void helloWorld() { printf("Hello world!"); }
Default arguments are function parameters for which a default value is implied when not explicitly stated. int foo(int x, int base=10 ) { return( x%base); } The above function assumes 'base' is 10 unless you specify otherwise when making the call. Thus calling foo(15) will return 5, as will foo(5,10), but foo(15,16) will return 15. Note that default parameters must appear after all non-default parameters in a function declaration. Once you specify a default parameter, all other parameters that follow must also have default values. Note also that when the definition of a function is split from its declaration, only the declaration should declare the default parameters: // Declaration: int foo(int x, int base=10 ); // Definition: int foo(int x, int base ) { return( x%base); }