On an average, the following assumptions will stand good for an induction motor: * Starting current (Ist) will be 5 times of the Full Load Amps (IFLA) * No Load Amps (INLA) can be any where between 0.3 to 0.5 times of IFLA; To the most, this figure depends upon the frame size of the motor; larger the frame size, smaller will be the INLA. This is also true for the wound rotor type induction motors. Manufacturers normally give two different current figures, one for the motor running with full load, and one for 'locked rotor'. Locked rotor current is the very high current drawn when power has been applied, but the motor has not had time to start spinning. <><><> No load current is important since this portion of the energy consumed will not be reflected in the process output, for a machine which is running continuously, no one can neglect whatever low value it is. Usually, the efficiencies will be mentioned and one can apply basic thumb rules to arrive no load current from those figures <><><> Manufacturers don't usually publish 'current at no load' for their motors. Since a motor with no load is not doing anything useful, no one really cares how much current is being drawn. It's kind of like putting your car up on a jack so the wheels are off the ground and asking how much fuel will the car burn sitting still with the wheels turning at 10 miles an hour - or at 100 miles per hour - who cares? !!!
Full load current ofthe motor x 0.58
The first thing you have to do is find the full load amps of the motor. The wire size feeding the motor has to be 125% of the full load current. The breaker is usually 250% of the full load current. If the voltage and amperage had been added to the question the exact breaker size could have been calculated.
How do you calculate voltage drop for starting motor current
This is a good indication that the motor is being overloaded. If the motor load is belt driven, remove the belt and then check the motor amps. If it goes back to normal FLA then there is a problem with the driven load. If the motor amperage stays high check the motor bearings for the problem.
The ratio is between 30% to 40 %
Full load starting current is typically in the region of 5or 6 times the full load motor current;.
Full load current ofthe motor x 0.58
To calculate the DG set current, you need the load current and the load voltage. To convert it into kilowatts it is divided by 1000.
As the no load current is the current due to core losses of the motor which is very small .in no load terminals are open circuited no current flows through it, a small current flows which is due to core
To calculate the DG set current, you need the load current and the load voltage. To convert it into kilowatts it is divided by 1000.
The first thing you have to do is find the full load amps of the motor. The wire size feeding the motor has to be 125% of the full load current. The breaker is usually 250% of the full load current. If the voltage and amperage had been added to the question the exact breaker size could have been calculated.
To calculate the range of an MCB (Miniature Circuit Breaker) for a motor circuit, you need to consider the full load current of the motor in amps and select an MCB with a rating above this value to ensure it can handle the starting current and any potential overload conditions without tripping. It is recommended to select an MCB that is rated at least 1.5 times the full load current of the motor to provide a safety margin and prevent nuisance tripping.
How do you calculate voltage drop for starting motor current
Motors with same horse-powers have different full load amps when operating. To calculate the size of wire to supply the motor feeder the voltage or current of the motor has to be known.
whenever the load increases,the current drawn by the motor to do or to fulfill the required energy to the load. so the current will increase generally.Increase in load will cause the full utilization of motor,so speed of rotor will decrease.
This is a good indication that the motor is being overloaded. If the motor load is belt driven, remove the belt and then check the motor amps. If it goes back to normal FLA then there is a problem with the driven load. If the motor amperage stays high check the motor bearings for the problem.
The ratio is between 30% to 40 %