The current-carrying capacity of a cable depends on a number of things in addition to its cross-sectional area; these include the type of conductor, number of cores, type of insulation, whether or not it is armoured, method of installation, etc. Accordingly, to determine its current-carrying capacity, you will need to refer to your national electrical code. For example, in the UK, BS 7671:2008 Requirements for Electrical Installations contains tables for all standard cable types, specifying current-carrying capacity, voltage drops, etc.
It is nothing but how much current or voltage taken in the circuit. It is known as Magnitude.
Without a load the secondary current is zero, by definition.
I(current) = V(voltage)/R(resistence) Example : 220 V / 5000 Ohm = 0.044 A (Ampère) = 44mA
I(current) = V(voltage)/R(resistence) Example : 220 V / 5000 Ohm = 0.044 A (Ampère) = 44mA
The method I have seen employed is to estimate the maximum current that will flow in the secondary side of the CT due to fault currents on the primary side, and calculate the total load (resistance) on the secondary side, including the CT resistance, cable resistance (2 way for ground faults, 1 way for three phase and L-L), resistance of any meters/relays connected to the CT. Once this is known, the voltage rise in the CT can be determined to see if the CT is likely to saturate.Alternately, you can determine the VA burden by the above, VA = V*I = (I*R)*I, using Ohm's law.The above answers the question of how to calculate the VA burdon on a current transformer. The VA burden of a CT is determined by the resistivity of the CT, multiplied by the current squared through the secondary. In general, this will be provided by the manufacturer in the form of a CT burden characteristic, developed through testing of the CT in question, not through calculations.
It is nothing but how much current or voltage taken in the circuit. It is known as Magnitude.
Without a load the secondary current is zero, by definition.
Cable doesn't conduct power, it conducts current. Either the voltage and load must be known or the amperage the cable will need to conduct to determine the size of the cable. Once the amperage is known, there are multiple tables online that have cable size and amperage. Do a Google search for "conductor amperage" for examples.
To calculate the heat capacity of a calorimeter, you can use the formula Q mcT, where Q is the heat absorbed or released, m is the mass of the substance, c is the specific heat capacity, and T is the change in temperature. By measuring the temperature change when a known amount of heat is added to the calorimeter, you can determine its heat capacity.
DC Current divided by 1.225
To calculate wattage, you need to multiply the voltage (V) by the current (I). The formula is: Wattage (W) = Voltage (V) x Current (I). This formula applies to electrical circuits where the voltage is known and the current is flowing.
-- Connect a source of known, small voltage across the ends of the unknown resistance. -- Measure the resulting current through the unknown resistance. -- Divide (small known voltage)/(measured current). The quotient is the formerly unknown resistance.
The capacity of a container can be measured by determining the maximum amount of liquid or material it can hold. This can be done by filling the container with a known quantity of water and measuring the volume, or by using the container's dimensions to calculate its capacity based on its shape.
To calculate the heat capacity of a calorimeter containing water, you can use the formula Q mcT, where Q is the heat absorbed or released, m is the mass of water, c is the specific heat capacity of water, and T is the change in temperature. By measuring the temperature change when a known amount of heat is added or removed from the water in the calorimeter, you can determine the heat capacity of the calorimeter.
If the wattage of a load is known then the current can be calculated. Watts equals amps times volts. You would use the following formula, Amps = Watts/Volts.
I(current) = V(voltage)/R(resistence) Example : 220 V / 5000 Ohm = 0.044 A (Ampère) = 44mA
They usually just measure current used and assume a known voltage.