How do you convert decimal number to binary number using while loop?

Answer 1

#include<stdio.h>

#include<conio.h>

#include<math.h>

void main()

{

long int a[20],i,n,count=0,b[20],c[20],sum=0;

printf("ENter the number in binary form=\t");

scanf("%ld",&n); // Get a binary number from the user

for (i=0;n>=1;i++)

{

a[i]=n%10;

n=n/10; // Loop To reverse the number And put all reversed numbers in arry a[i]

count=count + 1; // count to count the number of times this loop runs

}

for (i=0;i<=count-1;i++) // count -1 condition is used to run the loop till the previous loop run

{

b[i]=pow(2,i); // This is to raise the power of 2 to no of times previous loop runned.

}

for (i=0;i<=count-1;i++)

{

c[i]=a[i] * b[i]; // Multiply a[i] or reveresed binary no with b[i] or increasing pow of 2 to count-1

sum=sum +c[i]; // it is to add the c[i] elements with each other n put into sum variable.

}

printf("Decimal form =%ld",sum); // printing the sum to get the decimal form

getch();

}

// Hope it solves your problem, ANy more assistance honey.gupta13@Yahoo.com ffffff

Answer 2

#include<stdio.h>

#include<conio.h>

void main()

{

char base16[16]={'0','1','2','3','4','5','6','7','8','9','A','B','C','D','E','F'};

long num;

long cnum[68];

int base,number,i,j;

clrscr();

printf("\nEnter a decimal number to convert : ");

scanf("%ld",&num);

printf("\nEnter base for convert : 2(for binary),8(for octal),16(for hexadecimal) : ");

scanf("%d",&base);

i=0;

while(num!=0)

{

cnum[i]=num%base;

num=num/base;

i++;

}

i=i--;

printf("\nThe number in your base is : ");

for(i=i;i>=0;i--)

{

number=cnum[i];

printf("%c",base16[number]);

}

getch();

}